8.
\begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{4ba4a815-f53d-4de2-810b-b06e145f457b-24_547_629_242_717}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{figure}
Figure 1 shows the vertical cross section of a child's spinning top. The point \(A\) is vertically above the point \(B\) and the height of the spinning top is 5 cm .
The line \(C D\) is perpendicular to \(A B\) such that \(C D\) is the maximum width of the spinning top.
The spinning top is modelled as the solid of revolution created when part of the curve with polar equation
$$r ^ { 2 } = 25 \cos 2 \theta$$
is rotated through \(2 \pi\) radians about the initial line.
- Show that, according to the model, the surface area of the spinning top is
$$k \pi ( 2 - \sqrt { 2 } ) \mathrm { cm } ^ { 2 }$$
where \(k\) is a constant to be determined.
- Show that, according to the model, the length \(C D\) is \(\frac { 5 \sqrt { 2 } } { 2 } \mathrm {~cm}\).