Edexcel FM1 AS 2021 June — Question 4 13 marks

Exam BoardEdexcel
ModuleFM1 AS (Further Mechanics 1 AS)
Year2021
SessionJune
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions 1
TypeDirect collision with given impulse
DifficultyStandard +0.8 This is a multi-part Further Mechanics collision problem requiring application of both conservation of momentum and coefficient of restitution, with algebraic manipulation to show specific results, then solving a constraint equation involving the impulse. The presence of parameter e in both the mass and coefficient of restitution adds algebraic complexity beyond standard A-level mechanics, though the techniques themselves are standard for FM1.
Spec6.03b Conservation of momentum: 1D two particles6.03c Momentum in 2D: vector form6.03f Impulse-momentum: relation

  1. Two particles, \(P\) and \(Q\), have masses \(m\) and \(e m\) respectively. The particles are moving on a smooth horizontal plane in the same direction along the same straight line when they collide directly. The coefficient of restitution between \(P\) and \(Q\) is \(e\), where \(0 < e < 1\)
Immediately before the collision the speed of \(P\) is \(u\) and the speed of \(Q\) is \(e u\).
  1. Show that the speed of \(Q\) immediately after the collision is \(u\).
  2. Show that the direction of motion of \(P\) is unchanged by the collision. The magnitude of the impulse on \(Q\) in the collision is \(\frac { 2 } { 9 } m u\)
  3. Find the possible values of \(e\).

Question 4:
Part (a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Conservation of momentumM1 Correct no. of terms, allow consistent cancelled \(m\)'s: \(\left(u + e^2u = v_P + ev_Q\right)\)
\(mu + e^2mu = mv_P + emv_Q\)A1 Correct unsimplified equation
Newton's Impact LawM1 Correct no. of terms, with \(e\) on correct side
\(e(u - eu) = -v_P + v_Q\)A1 Correct unsimplified equation
Solve these equations for \(v_Q\)M1
\(v_Q = u^*\)A1*
Part (b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(v_P = u(e^2 - e + 1) \left(= \frac{(e^3+1)u}{e+1}\right)\)M1
\(= u\left(\left(e - \frac{1}{2}\right)^2 + \frac{3}{4}\right)\)A1
\(> 0\) so \(P\) continues to move in the same direction*A1*
Part (c):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Use impulse-momentum principleM1
\(I = em(u - eu)\) or \(m(-u(e^2 - e+1) - (-u))\) \((= (e - e^2)mu)\)A1
\((e - e^2) = \frac{2}{9}\) and solveM1
\(e = \frac{1}{3}\) or \(\frac{2}{3}\)A1
Question 4b:
AnswerMarks Guidance
Answer/WorkingMark Guidance Notes
Solve for \(v_p\)M1
Completing the square or any other appropriate methodM1
Correct conclusion correctly reachedA1* cao
Question 4c:
AnswerMarks Guidance
Answer/WorkingMark Guidance Notes
Correct no. of terms, dimensionally correct expression in terms of \(e\) and \(u\)M1 Must be subtracting. Needs to be in terms of \(e\) and \(u\)
Correct unsimplified expressionA1 Allow negative answer at this stage
Solving an appropriate quadratic equationM1
Two correct answersA1
## Question 4:

**Part (a):**

| Answer/Working | Mark | Guidance |
|---|---|---|
| Conservation of momentum | M1 | Correct no. of terms, allow consistent cancelled $m$'s: $\left(u + e^2u = v_P + ev_Q\right)$ |
| $mu + e^2mu = mv_P + emv_Q$ | A1 | Correct unsimplified equation |
| Newton's Impact Law | M1 | Correct no. of terms, with $e$ on correct side |
| $e(u - eu) = -v_P + v_Q$ | A1 | Correct unsimplified equation |
| Solve these equations for $v_Q$ | M1 | |
| $v_Q = u^*$ | A1* | |

**Part (b):**

| Answer/Working | Mark | Guidance |
|---|---|---|
| $v_P = u(e^2 - e + 1) \left(= \frac{(e^3+1)u}{e+1}\right)$ | M1 | |
| $= u\left(\left(e - \frac{1}{2}\right)^2 + \frac{3}{4}\right)$ | A1 | |
| $> 0$ so $P$ continues to move in the same direction* | A1* | |

**Part (c):**

| Answer/Working | Mark | Guidance |
|---|---|---|
| Use impulse-momentum principle | M1 | |
| $I = em(u - eu)$ or $m(-u(e^2 - e+1) - (-u))$ $(= (e - e^2)mu)$ | A1 | |
| $(e - e^2) = \frac{2}{9}$ and solve | M1 | |
| $e = \frac{1}{3}$ or $\frac{2}{3}$ | A1 | |

## Question 4b:

| Answer/Working | Mark | Guidance Notes |
|---|---|---|
| Solve for $v_p$ | M1 | |
| Completing the square or any other appropriate method | M1 | |
| Correct conclusion correctly reached | A1* | cao |

## Question 4c:

| Answer/Working | Mark | Guidance Notes |
|---|---|---|
| Correct no. of terms, dimensionally correct expression in terms of $e$ and $u$ | M1 | Must be subtracting. Needs to be in terms of $e$ and $u$ |
| Correct unsimplified expression | A1 | Allow negative answer at this stage |
| Solving an appropriate quadratic equation | M1 | |
| Two correct answers | A1 | |
\begin{enumerate}
  \item Two particles, $P$ and $Q$, have masses $m$ and $e m$ respectively. The particles are moving on a smooth horizontal plane in the same direction along the same straight line when they collide directly. The coefficient of restitution between $P$ and $Q$ is $e$, where $0 < e < 1$
\end{enumerate}

Immediately before the collision the speed of $P$ is $u$ and the speed of $Q$ is $e u$.\\
(a) Show that the speed of $Q$ immediately after the collision is $u$.\\
(b) Show that the direction of motion of $P$ is unchanged by the collision.

The magnitude of the impulse on $Q$ in the collision is $\frac { 2 } { 9 } m u$\\
(c) Find the possible values of $e$.

\hfill \mbox{\textit{Edexcel FM1 AS 2021 Q4 [13]}}