| Exam Board | Edexcel |
|---|---|
| Module | FM1 AS (Further Mechanics 1 AS) |
| Year | 2021 |
| Session | June |
| Marks | 13 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Momentum and Collisions 1 |
| Type | Direct collision with given impulse |
| Difficulty | Standard +0.8 This is a multi-part Further Mechanics collision problem requiring application of both conservation of momentum and coefficient of restitution, with algebraic manipulation to show specific results, then solving a constraint equation involving the impulse. The presence of parameter e in both the mass and coefficient of restitution adds algebraic complexity beyond standard A-level mechanics, though the techniques themselves are standard for FM1. |
| Spec | 6.03b Conservation of momentum: 1D two particles6.03c Momentum in 2D: vector form6.03f Impulse-momentum: relation |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| Conservation of momentum | M1 | Correct no. of terms, allow consistent cancelled \(m\)'s: \(\left(u + e^2u = v_P + ev_Q\right)\) |
| \(mu + e^2mu = mv_P + emv_Q\) | A1 | Correct unsimplified equation |
| Newton's Impact Law | M1 | Correct no. of terms, with \(e\) on correct side |
| \(e(u - eu) = -v_P + v_Q\) | A1 | Correct unsimplified equation |
| Solve these equations for \(v_Q\) | M1 | |
| \(v_Q = u^*\) | A1* |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| \(v_P = u(e^2 - e + 1) \left(= \frac{(e^3+1)u}{e+1}\right)\) | M1 | |
| \(= u\left(\left(e - \frac{1}{2}\right)^2 + \frac{3}{4}\right)\) | A1 | |
| \(> 0\) so \(P\) continues to move in the same direction* | A1* |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| Use impulse-momentum principle | M1 | |
| \(I = em(u - eu)\) or \(m(-u(e^2 - e+1) - (-u))\) \((= (e - e^2)mu)\) | A1 | |
| \((e - e^2) = \frac{2}{9}\) and solve | M1 | |
| \(e = \frac{1}{3}\) or \(\frac{2}{3}\) | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance Notes |
| Solve for \(v_p\) | M1 | |
| Completing the square or any other appropriate method | M1 | |
| Correct conclusion correctly reached | A1* | cao |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance Notes |
| Correct no. of terms, dimensionally correct expression in terms of \(e\) and \(u\) | M1 | Must be subtracting. Needs to be in terms of \(e\) and \(u\) |
| Correct unsimplified expression | A1 | Allow negative answer at this stage |
| Solving an appropriate quadratic equation | M1 | |
| Two correct answers | A1 |
## Question 4:
**Part (a):**
| Answer/Working | Mark | Guidance |
|---|---|---|
| Conservation of momentum | M1 | Correct no. of terms, allow consistent cancelled $m$'s: $\left(u + e^2u = v_P + ev_Q\right)$ |
| $mu + e^2mu = mv_P + emv_Q$ | A1 | Correct unsimplified equation |
| Newton's Impact Law | M1 | Correct no. of terms, with $e$ on correct side |
| $e(u - eu) = -v_P + v_Q$ | A1 | Correct unsimplified equation |
| Solve these equations for $v_Q$ | M1 | |
| $v_Q = u^*$ | A1* | |
**Part (b):**
| Answer/Working | Mark | Guidance |
|---|---|---|
| $v_P = u(e^2 - e + 1) \left(= \frac{(e^3+1)u}{e+1}\right)$ | M1 | |
| $= u\left(\left(e - \frac{1}{2}\right)^2 + \frac{3}{4}\right)$ | A1 | |
| $> 0$ so $P$ continues to move in the same direction* | A1* | |
**Part (c):**
| Answer/Working | Mark | Guidance |
|---|---|---|
| Use impulse-momentum principle | M1 | |
| $I = em(u - eu)$ or $m(-u(e^2 - e+1) - (-u))$ $(= (e - e^2)mu)$ | A1 | |
| $(e - e^2) = \frac{2}{9}$ and solve | M1 | |
| $e = \frac{1}{3}$ or $\frac{2}{3}$ | A1 | |
## Question 4b:
| Answer/Working | Mark | Guidance Notes |
|---|---|---|
| Solve for $v_p$ | M1 | |
| Completing the square or any other appropriate method | M1 | |
| Correct conclusion correctly reached | A1* | cao |
## Question 4c:
| Answer/Working | Mark | Guidance Notes |
|---|---|---|
| Correct no. of terms, dimensionally correct expression in terms of $e$ and $u$ | M1 | Must be subtracting. Needs to be in terms of $e$ and $u$ |
| Correct unsimplified expression | A1 | Allow negative answer at this stage |
| Solving an appropriate quadratic equation | M1 | |
| Two correct answers | A1 | |
\begin{enumerate}
\item Two particles, $P$ and $Q$, have masses $m$ and $e m$ respectively. The particles are moving on a smooth horizontal plane in the same direction along the same straight line when they collide directly. The coefficient of restitution between $P$ and $Q$ is $e$, where $0 < e < 1$
\end{enumerate}
Immediately before the collision the speed of $P$ is $u$ and the speed of $Q$ is $e u$.\\
(a) Show that the speed of $Q$ immediately after the collision is $u$.\\
(b) Show that the direction of motion of $P$ is unchanged by the collision.
The magnitude of the impulse on $Q$ in the collision is $\frac { 2 } { 9 } m u$\\
(c) Find the possible values of $e$.
\hfill \mbox{\textit{Edexcel FM1 AS 2021 Q4 [13]}}