CAIE P3 2021 November — Question 7 8 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2021
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFirst order differential equations (integrating factor)
TypeSeparable variables
DifficultyStandard +0.3 Part (a) is routine differentiation using chain rule. Part (b) is a standard separable differential equation requiring separation, integration, and applying initial conditions. Part (c) is a simple limit evaluation. All techniques are straightforward applications of core methods with no novel insight required, making this slightly easier than average.
Spec1.07l Derivative of ln(x): and related functions1.08k Separable differential equations: dy/dx = f(x)g(y)

7
  1. Given that \(y = \ln ( \ln x )\), show that $$\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { 1 } { x \ln x }$$ The variables \(x\) and \(t\) satisfy the differential equation $$x \ln x + t \frac { \mathrm {~d} x } { \mathrm {~d} t } = 0$$ It is given that \(x = \mathrm { e }\) when \(t = 2\).
  2. Solve the differential equation obtaining an expression for \(x\) in terms of \(t\), simplifying your answer.
  3. Hence state what happens to the value of \(x\) as \(t\) tends to infinity.

Question 7(a):
AnswerMarks
Show sufficient working to justify the given answerB1
Total: 1
Question 7(b):
AnswerMarks Guidance
Correct separation of variablesB1 e.g. \(-\int \frac{1}{t}dt = \int \frac{1}{x\ln x}dx\)
Obtain term \(\ln(\ln x)\)B1
Obtain term \(-\ln t\)B1
Evaluate a constant or use \(x = e\) and \(t = 2\) as limits in an expression involving \(\ln(\ln x)\)M1
Obtain correct solution in any form, e.g. \(\ln(\ln x) = -\ln t + \ln 2\)A1
Use log laws to enable removal of logarithmsM1
Obtain answer \(x = e^{\frac{2}{t}}\), or simplified equivalentA1
Total: 7
Question 7(c):
AnswerMarks
State that \(x\) tends to 1 coming from \(x = e^{\frac{k}{t}}\)B1
Total: 1
## Question 7(a):
| Show sufficient working to justify the given answer | B1 | |
| **Total: 1** | | |

## Question 7(b):
| Correct separation of variables | B1 | e.g. $-\int \frac{1}{t}dt = \int \frac{1}{x\ln x}dx$ |
| Obtain term $\ln(\ln x)$ | B1 | |
| Obtain term $-\ln t$ | B1 | |
| Evaluate a constant or use $x = e$ and $t = 2$ as limits in an expression involving $\ln(\ln x)$ | M1 | |
| Obtain correct solution in any form, e.g. $\ln(\ln x) = -\ln t + \ln 2$ | A1 | |
| Use log laws to enable removal of logarithms | M1 | |
| Obtain answer $x = e^{\frac{2}{t}}$, or simplified equivalent | A1 | |
| **Total: 7** | | |

## Question 7(c):
| State that $x$ tends to 1 coming from $x = e^{\frac{k}{t}}$ | B1 | |
| **Total: 1** | | |

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7
\begin{enumerate}[label=(\alph*)]
\item Given that $y = \ln ( \ln x )$, show that

$$\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { 1 } { x \ln x }$$

The variables $x$ and $t$ satisfy the differential equation

$$x \ln x + t \frac { \mathrm {~d} x } { \mathrm {~d} t } = 0$$

It is given that $x = \mathrm { e }$ when $t = 2$.
\item Solve the differential equation obtaining an expression for $x$ in terms of $t$, simplifying your answer.
\item Hence state what happens to the value of $x$ as $t$ tends to infinity.
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2021 Q7 [8]}}