Easy -1.2 This is a straightforward application of the definition of cumulative distribution function: P(Y > 4) = 1 - F(4) = 1 - 16/36 = 5/9. Requires only direct substitution into a given formula with no problem-solving or conceptual insight, making it easier than average even for Further Maths statistics.
2 The continuous random variable \(Y\) has cumulative distribution function defined by
$$\mathrm { F } ( y ) = \left\{ \begin{array} { c c }
0 & y < 0 \\
\frac { y ^ { 2 } } { 36 } & 0 \leq y \leq 6 \\
1 & y > 6
\end{array} \right.$$
Find the value of \(\mathrm { P } ( Y > 4 )\)
Circle your answer.
\(\frac { 4 } { 9 }\)
\(\frac { 5 } { 9 }\)
\(\frac { 16 } { 27 }\)
\(\frac { 11 } { 27 }\)
2 The continuous random variable $Y$ has cumulative distribution function defined by
$$\mathrm { F } ( y ) = \left\{ \begin{array} { c c }
0 & y < 0 \\
\frac { y ^ { 2 } } { 36 } & 0 \leq y \leq 6 \\
1 & y > 6
\end{array} \right.$$
Find the value of $\mathrm { P } ( Y > 4 )$\\
Circle your answer.\\
$\frac { 4 } { 9 }$\\
$\frac { 5 } { 9 }$\\
$\frac { 16 } { 27 }$\\
$\frac { 11 } { 27 }$
\hfill \mbox{\textit{AQA Further Paper 3 Statistics Q2 [1]}}