10 Ben takes an underground train to work and back home each day. The waiting time is defined as the time from when he reaches the station platform until he boards the train.
On his way to work the waiting time is \(X\) minutes, where \(X\) is modelled by a continuous uniform distribution on \([ 0,6 ]\).
On his way back from work, the waiting time is \(Y\) minutes, where \(Y\) is modelled by a continuous uniform distribution on [0,4].
Ben's total waiting time for both journeys is \(Z\) minutes, where \(Z = X + Y\). You should assume that \(X\) and \(Y\) are independent.
- Find \(\mathrm { E } ( \mathrm { Z } )\).
- Ben thinks that \(Z\) will be well modelled by a continuous uniform distribution on \([ 0,10 ]\).
By considering variances, show that he is not correct.
- Ben's friend Jamila constructs the spreadsheet below, which shows a simulation of 20 values of \(X , Y\) and \(Z\). All of the values have been rounded to 2 decimal places.
| \multirow[b]{3}{*}{} | A | B | C |
| X | Y | Z |
| 1.17 | 3.83 | 5.01 |
| 3 | 2.01 | 0.81 | 2.82 |
| 4 | 1.27 | 1.52 | 2.78 |
| 5 | 1.41 | 3.94 | 5.35 |
| 6 | 4.11 | 2.94 | 7.05 |
| 7 | 1.76 | 0.96 | 2.72 |
| 8 | 3.29 | 0.98 | 4.27 |
| 9 | 0.77 | 0.22 | 0.99 |
| 10 | 0.99 | 1.44 | 2.43 |
| 11 | 4.79 | 2.43 | 7.22 |
| 12 | 3.82 | 3.93 | 7.75 |
| 13 | 5.25 | 2.74 | 7.99 |
| 14 | 2.64 | 0.48 | 3.12 |
| 15 | 1.54 | 2.18 | 3.72 |
| 16 | 2.71 | 1.66 | 4.36 |
| 17 | 0.04 | 3.24 | 3.28 |
| 18 | 5.95 | 3.12 | 9.07 |
| 19 | 5.22 | 1.21 | 6.42 |
| 20 | 4.16 | 0.11 | 4.27 |
| 21 | 1.02 | 0.99 | 2.01 |
| 22 | | | |
Write down an estimate of \(\mathrm { P } ( Z > 6 )\). - Use a Normal approximation to determine the probability that Ben's total waiting time when travelling to and from work on 40 days is more than 210 minutes.