OCR MEI Further Mechanics Minor Specimen — Question 1 4 marks

Exam BoardOCR MEI
ModuleFurther Mechanics Minor (Further Mechanics Minor)
SessionSpecimen
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions
TypeCalculate impulse from force-time data
DifficultyModerate -0.8 This is a straightforward application of impulse = force × time and the impulse-momentum theorem. The vector arithmetic is simple (scalar multiplication and addition), and the method is direct recall with no problem-solving insight required. Easier than average A-level mechanics.
Spec6.03e Impulse: by a force6.03f Impulse-momentum: relation

1 In this question, \(\mathbf { i }\) and \(\mathbf { j }\) are perpendicular unit vectors in a horizontal plane. A particle \(P\) has mass 10 kg and a speed of \(20 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) in the direction of \(4 \mathbf { i } + 3 \mathbf { j }\). A force of \(( - 4 \mathbf { i } + 15 \mathbf { j } ) \mathrm { N }\) acts on P for 8 seconds.
  1. Calculate the impulse of the force over the 8 seconds.
  2. Hence find the speed of P at the end of the 8 seconds.

Question 1:
AnswerMarks Guidance
1(i) 8(cid:11)(cid:16)4i(cid:14)15j(cid:12)(cid:32)(cid:11)(cid:16)32i(cid:14)120j(cid:12)
Impulse is NsB1
[1]1.2
1(ii) Initial momentum is
20
(cid:11)4i(cid:14)3j(cid:12)(cid:117)10(cid:32)(cid:11)160i(cid:14)120j(cid:12) Ns
5
10v(cid:32)(cid:11)160i(cid:14)120j(cid:12)(cid:14)(cid:11)(cid:16)32i(cid:14)120j(cid:12)(cid:32)(cid:11)128i(cid:14)240j(cid:12)
AnswerMarks
so v (cid:32)27.2 and speed is 27.2ms -1B1
M1
A1
AnswerMarks
[3]1.1
3.4
AnswerMarks
1.1Any form. May be implied
N
EUse of I(cid:32)mv–mu
Question 1:
1 | (i) | 8(cid:11)(cid:16)4i(cid:14)15j(cid:12)(cid:32)(cid:11)(cid:16)32i(cid:14)120j(cid:12)
Impulse is Ns | B1
[1] | 1.2
1 | (ii) | Initial momentum is
20
(cid:11)4i(cid:14)3j(cid:12)(cid:117)10(cid:32)(cid:11)160i(cid:14)120j(cid:12) Ns
5
10v(cid:32)(cid:11)160i(cid:14)120j(cid:12)(cid:14)(cid:11)(cid:16)32i(cid:14)120j(cid:12)(cid:32)(cid:11)128i(cid:14)240j(cid:12)
so v (cid:32)27.2 and speed is 27.2ms -1 | B1
M1
A1
[3] | 1.1
3.4
1.1 | Any form. May be implied
N
EUse of I(cid:32)mv–mu
1 In this question, $\mathbf { i }$ and $\mathbf { j }$ are perpendicular unit vectors in a horizontal plane.

A particle $P$ has mass 10 kg and a speed of $20 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ in the direction of $4 \mathbf { i } + 3 \mathbf { j }$. A force of $( - 4 \mathbf { i } + 15 \mathbf { j } ) \mathrm { N }$ acts on P for 8 seconds.\\
(i) Calculate the impulse of the force over the 8 seconds.\\
(ii) Hence find the speed of P at the end of the 8 seconds.

\hfill \mbox{\textit{OCR MEI Further Mechanics Minor  Q1 [4]}}