OCR MEI Further Pure Core 2019 June — Question 5 5 marks

Exam BoardOCR MEI
ModuleFurther Pure Core (Further Pure Core)
Year2019
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTaylor series
TypeCombining or manipulating standard series
DifficultyStandard +0.3 This question requires knowing the standard Maclaurin series for cos(2x), applying the identity sin²x = (1-cos(2x))/2, and performing straightforward algebraic manipulation to extract coefficients. While it involves multiple steps and the identity may not be immediately obvious to all students, it's a fairly standard Further Maths exercise in series manipulation with no novel problem-solving required—slightly easier than average.
Spec4.08b Standard Maclaurin series: e^x, sin, cos, ln(1+x), (1+x)^n

5 Using the Maclaurin series for \(\cos 2 x\), show that, for small values of \(x\), \(\sin ^ { 2 } x \approx a x ^ { 2 } + b x ^ { 4 } + c x ^ { 6 }\),
where the values of \(a , b\) and \(c\) are to be given in exact form.

Question 5:
AnswerMarks
5(2x)2 (2x)4 (2x)6
cos2x1   ...
2! 4! 6!
2 4
12x2 x4 x6...
3 45
sin2x = ½ (1 – cos 2x)
1 2 4
 (112x2 x4 x6...)
2 3 45
1 2 1 2
x2 x4 x6... so a1,b ,c
AnswerMarks
3 45 3 45M1
A1
M1
A2,1,0
AnswerMarks
[5]1.1a
1.1b
3.1a
AnswerMarks
1.1bat least 3 terms correct
Allow unsimplified fractions
AnswerMarks
(without factorials)or good attempt from 1st
principles
Question 5:
5 | (2x)2 (2x)4 (2x)6
cos2x1   ...
2! 4! 6!
2 4
12x2 x4 x6...
3 45
sin2x = ½ (1 – cos 2x)
1 2 4
 (112x2 x4 x6...)
2 3 45
1 2 1 2
x2 x4 x6... so a1,b ,c
3 45 3 45 | M1
A1
M1
A2,1,0
[5] | 1.1a
1.1b
3.1a
1.1b | at least 3 terms correct
Allow unsimplified fractions
(without factorials) | or good attempt from 1st
principles
5 Using the Maclaurin series for $\cos 2 x$, show that, for small values of $x$, $\sin ^ { 2 } x \approx a x ^ { 2 } + b x ^ { 4 } + c x ^ { 6 }$,\\
where the values of $a , b$ and $c$ are to be given in exact form.

\hfill \mbox{\textit{OCR MEI Further Pure Core 2019 Q5 [5]}}