OCR MEI Further Statistics A AS Specimen — Question 1 6 marks

Exam BoardOCR MEI
ModuleFurther Statistics A AS (Further Statistics A AS)
SessionSpecimen
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPoisson distribution
TypeSingle scaled time period
DifficultyModerate -0.8 This is a straightforward application of standard Poisson distribution properties and calculations. Parts (i) and (iii) test basic recall (variance equals mean, scaling property), while parts (ii) and (iv) require routine use of the Poisson probability formula with no conceptual challenges or problem-solving insight needed.
Spec5.02i Poisson distribution: random events model5.02j Poisson formula: P(X=x) = e^(-lambda)*lambda^x/x!5.02k Calculate Poisson probabilities5.02l Poisson conditions: for modelling5.02m Poisson: mean = variance = lambda

1 The number of failures of a machine each week at a factory is modelled by a Poisson distribution with mean 0.45.
  1. Write down the variance of the distribution.
  2. Find the probability that there are exactly 2 failures in a week.
  3. State a distribution which can be used to model the number of failures in a period of 4 weeks.
  4. Find the probability that there are at least 2 failures in a period of 4 weeks.

Question 1:
AnswerMarks Guidance
1(i) Variance = 0.45
[1]1.2
(ii)P(2 failures) = 0.0646 B1
[1]1.1 BC
(iii)Poisson
Parameter = 1.8B1
B1
AnswerMarks
[2]3.3
1.1aN
(iv)Using λ = 1.8
P(at least 2 in 4 weeks) = 1 – 0.4628
AnswerMarks
= 0.5372M1
A1
AnswerMarks
[2]1.1a
1.1E
For 0.4628 OR 1 - P(Y ≤ 1)
BC cao
AnswerMarks Guidance
11 2

AnswerMarks Guidance
1(i)1 0

AnswerMarks Guidance
1(ii)1 0

AnswerMarks Guidance
1(iii)1 0

AnswerMarks Guidance
1(iv)2 0
Question 1:
1 | (i) | Variance = 0.45 | B1
[1] | 1.2
(ii) | P(2 failures) = 0.0646 | B1
[1] | 1.1 | BC
(iii) | Poisson
Parameter = 1.8 | B1
B1
[2] | 3.3
1.1a | N
(iv) | Using λ = 1.8
P(at least 2 in 4 weeks) = 1 – 0.4628
= 0.5372 | M1
A1
[2] | 1.1a
1.1 | E
For 0.4628 OR 1 - P(Y ≤ 1)
BC cao
1 | 1 | 2 | 3 | 4 | 5 | 6
--- 1(i) ---
1(i) | 1 | 0 | 0 | 0 | 1
--- 1(ii) ---
1(ii) | 1 | 0 | 0 | 0 | 1
--- 1(iii) ---
1(iii) | 1 | 0 | 0 | 1 | 2
--- 1(iv) ---
1(iv) | 2 | 0 | 0 | 0 | 2
1 The number of failures of a machine each week at a factory is modelled by a Poisson distribution with mean 0.45.\\
(i) Write down the variance of the distribution.\\
(ii) Find the probability that there are exactly 2 failures in a week.\\
(iii) State a distribution which can be used to model the number of failures in a period of 4 weeks.\\
(iv) Find the probability that there are at least 2 failures in a period of 4 weeks.

\hfill \mbox{\textit{OCR MEI Further Statistics A AS  Q1 [6]}}