AQA FP1 2010 June — Question 3 5 marks

Exam BoardAQA
ModuleFP1 (Further Pure Mathematics 1)
Year2010
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTrig Graphs & Exact Values
TypeFind general solution of trig equation
DifficultyModerate -0.3 This is a straightforward application of the general solution formula for cos θ = cos α, requiring students to recall that solutions are θ = ±α + 360n°. The algebraic manipulation to solve for x is minimal (adding 20° and dividing by 5). While it's from FP1, this particular question is more routine than typical Further Maths content, being slightly easier than an average A-level question due to its direct application of a standard formula with no conceptual complications.
Spec1.05o Trigonometric equations: solve in given intervals

3 Find the general solution, in degrees, of the equation $$\cos \left( 5 x - 20 ^ { \circ } \right) = \cos 40 ^ { \circ }$$
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Question 3:
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(5x - 20 = \pm 40 + 360n°\)M1 Using \(\cos A = \cos B \Rightarrow A = \pm B + 360n°\)
Case 1: \(5x - 20 = 40 + 360n°\)M1 Correct split into two cases
\(5x = 60 + 360n°\)
\(x = 12 + 72n°\)A1 Correct first family
Case 2: \(5x - 20 = -40 + 360n°\)
\(5x = -20 + 360n°\)
\(x = -4 + 72n°\)A1 Correct second family
Both answers expressed with \(n\) as integerA1 General solution fully correct
# Question 3:

| Answer/Working | Mark | Guidance |
|---|---|---|
| $5x - 20 = \pm 40 + 360n°$ | M1 | Using $\cos A = \cos B \Rightarrow A = \pm B + 360n°$ |
| Case 1: $5x - 20 = 40 + 360n°$ | M1 | Correct split into two cases |
| $5x = 60 + 360n°$ | | |
| $x = 12 + 72n°$ | A1 | Correct first family |
| Case 2: $5x - 20 = -40 + 360n°$ | | |
| $5x = -20 + 360n°$ | | |
| $x = -4 + 72n°$ | A1 | Correct second family |
| Both answers expressed with $n$ as integer | A1 | General solution fully correct |

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3 Find the general solution, in degrees, of the equation

$$\cos \left( 5 x - 20 ^ { \circ } \right) = \cos 40 ^ { \circ }$$

\begin{center}
\includegraphics[max width=\textwidth, alt={}]{763d89e4-861a-4754-a93c-d0902987673f-04_2228_1705_475_155}
\end{center}

\hfill \mbox{\textit{AQA FP1 2010 Q3 [5]}}