Edexcel M5 2009 June — Question 4

Exam BoardEdexcel
ModuleM5 (Mechanics 5)
Year2009
SessionJune
TopicCentre of Mass 2

4. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{a11940cb-73a8-4f33-bfbc-73841320c1dc-07_515_415_210_758} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} A uniform lamina of mass \(M\) is in the shape of a right-angled triangle \(O A B\). The angle \(O A B\) is \(90 ^ { \circ } , O A = a\) and \(A B = 2 a\), as shown in Figure 1.
  1. Prove, using integration, that the moment of inertia of the lamina \(O A B\) about the edge \(O A\) is \(\frac { 2 } { 3 } M a ^ { 2 }\).
    (You may assume without proof that the moment of inertia of a uniform rod of mass \(m\) and length \(2 l\) about an axis through one end and perpendicular to the rod is \(\frac { 4 } { 3 } m l ^ { 2 }\).) The lamina \(O A B\) is free to rotate about a fixed smooth horizontal axis along the edge \(O A\) and hangs at rest with \(B\) vertically below \(A\). The lamina is then given a horizontal impulse of magnitude \(J\). The impulse is applied to the lamina at the point \(B\), in a direction which is perpendicular to the plane of the lamina. Given that the lamina first comes to instantaneous rest after rotating through an angle of \(120 ^ { \circ }\),
  2. find an expression for \(J\), in terms of \(M , a\) and \(g\).