OCR MEI M4 2009 June — Question 2 12 marks

Exam BoardOCR MEI
ModuleM4 (Mechanics 4)
Year2009
SessionJune
Marks12
PaperDownload PDF ↗
TopicMoments
TypePotential energy with elastic strings/springs
DifficultyChallenging +1.2 This is a standard M4 potential energy method question requiring setup of gravitational and elastic PE, differentiation, and stability analysis via second derivative. The geometry is straightforward (vertical string above hinged rod), and the method is routine for this module, though it requires careful bookkeeping across multiple steps and understanding of the energy-equilibrium relationship.
Spec3.04b Equilibrium: zero resultant moment and force6.02i Conservation of energy: mechanical energy principle6.02j Conservation with elastics: springs and strings

2 A uniform rigid rod AB of mass \(m\) and length \(4 a\) is freely hinged at the end A to a horizontal rail. The end B is attached to a light elastic string BC of modulus \(\frac { 1 } { 2 } m g\) and natural length \(a\). The end C of the string is attached to a ring which is small, light and smooth. The ring can slide along the rail and is always vertically above B . The angle that AB makes below the rail is \(\theta\). The system is shown in Fig. 2. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{9763e6c4-e372-46ef-a666-3ccb185aa5d2-2_277_707_1398_717} \captionsetup{labelformat=empty} \caption{Fig. 2}
\end{figure}
  1. Find the potential energy, \(V\), of the system when the string is stretched and show that $$\frac { \mathrm { d } V } { \mathrm {~d} \theta } = 4 m g a \cos \theta ( 2 \sin \theta - 1 )$$
  2. Hence find any positions of equilibrium of the system and investigate their stability.

2 A uniform rigid rod AB of mass $m$ and length $4 a$ is freely hinged at the end A to a horizontal rail. The end B is attached to a light elastic string BC of modulus $\frac { 1 } { 2 } m g$ and natural length $a$. The end C of the string is attached to a ring which is small, light and smooth. The ring can slide along the rail and is always vertically above B . The angle that AB makes below the rail is $\theta$. The system is shown in Fig. 2.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{9763e6c4-e372-46ef-a666-3ccb185aa5d2-2_277_707_1398_717}
\captionsetup{labelformat=empty}
\caption{Fig. 2}
\end{center}
\end{figure}

(i) Find the potential energy, $V$, of the system when the string is stretched and show that

$$\frac { \mathrm { d } V } { \mathrm {~d} \theta } = 4 m g a \cos \theta ( 2 \sin \theta - 1 )$$

(ii) Hence find any positions of equilibrium of the system and investigate their stability.

\hfill \mbox{\textit{OCR MEI M4 2009 Q2 [12]}}