OCR MEI M3 2009 June — Question 1 19 marks

Exam BoardOCR MEI
ModuleM3 (Mechanics 3)
Year2009
SessionJune
Marks19
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircular Motion 2
TypeParticle on outer surface of sphere
DifficultyStandard +0.3 This is a standard M3 circular motion question with familiar particle-on-sphere setup. Part (i) is routine energy conservation (show that), parts (ii-iii) apply standard formulas for normal reaction and leaving condition, and part (iv) is straightforward resolution of forces in conical pendulum geometry. All techniques are textbook exercises requiring minimal problem-solving insight.
Spec3.03d Newton's second law: 2D vectors6.05a Angular velocity: definitions6.05c Horizontal circles: conical pendulum, banked tracks6.05e Radial/tangential acceleration

1 A fixed solid sphere has centre O and radius 2.6 m . A particle P of mass 0.65 kg moves on the smooth surface of the sphere. The particle P is set in motion with horizontal velocity \(1.4 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) at the highest point of the sphere, and moves in part of a vertical circle. When OP makes an angle \(\theta\) with the upward vertical, and P is still in contact with the sphere, the speed of P is \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
  1. Show that \(v ^ { 2 } = 52.92 - 50.96 \cos \theta\).
  2. Find, in terms of \(\theta\), the normal reaction acting on P .
  3. Find the speed of P at the instant when it leaves the surface of the sphere. The particle P is now attached to one end of a light inextensible string, and the other end of the string is fixed to a point A , vertically above O , such that AP is tangential to the sphere, as shown in Fig. 1. P moves with constant speed \(1.2 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) in a horizontal circle with radius 2.4 m on the surface of the sphere. \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{3ec81c4e-e0fa-43d9-9c79-ef9df746be8f-2_1100_634_1089_753} \captionsetup{labelformat=empty} \caption{Fig. 1}
    \end{figure}
  4. Find the tension in the string and the normal reaction acting on P .

1 A fixed solid sphere has centre O and radius 2.6 m . A particle P of mass 0.65 kg moves on the smooth surface of the sphere.

The particle P is set in motion with horizontal velocity $1.4 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ at the highest point of the sphere, and moves in part of a vertical circle. When OP makes an angle $\theta$ with the upward vertical, and P is still in contact with the sphere, the speed of P is $v \mathrm {~m} \mathrm {~s} ^ { - 1 }$.\\
(i) Show that $v ^ { 2 } = 52.92 - 50.96 \cos \theta$.\\
(ii) Find, in terms of $\theta$, the normal reaction acting on P .\\
(iii) Find the speed of P at the instant when it leaves the surface of the sphere.

The particle P is now attached to one end of a light inextensible string, and the other end of the string is fixed to a point A , vertically above O , such that AP is tangential to the sphere, as shown in Fig. 1. P moves with constant speed $1.2 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ in a horizontal circle with radius 2.4 m on the surface of the sphere.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{3ec81c4e-e0fa-43d9-9c79-ef9df746be8f-2_1100_634_1089_753}
\captionsetup{labelformat=empty}
\caption{Fig. 1}
\end{center}
\end{figure}

(iv) Find the tension in the string and the normal reaction acting on P .

\hfill \mbox{\textit{OCR MEI M3 2009 Q1 [19]}}