OCR M3 2013 June — Question 2 8 marks

Exam BoardOCR
ModuleM3 (Mechanics 3)
Year2013
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicOblique and successive collisions
TypeBall bouncing on horizontal surface
DifficultyStandard +0.3 This is a standard projectile motion problem combined with coefficient of restitution, requiring multiple connected steps but using routine M3 techniques: SUVAT for vertical motion to find impact velocity, restitution formula for bounce velocity, and impulse-momentum theorem. All methods are textbook applications with no novel insight required, making it slightly above average difficulty due to the multi-part nature and careful bookkeeping needed.
Spec3.02h Motion under gravity: vector form6.03e Impulse: by a force6.03f Impulse-momentum: relation6.03j Perfectly elastic/inelastic: collisions

2 A particle of mass 0.3 kg is projected horizontally under gravity with velocity \(3.5 \mathrm {~ms} ^ { - 1 }\) from a point 0.4 m above a smooth horizontal plane. The particle first hits the plane at point \(A\); it bounces and hits the plane a second time at point \(B\). The distance \(A B\) is 1 m . Calculate
  1. the vertical component of the velocity of the particle when it arrives at \(A\), and the time taken for the particle to travel from \(A\) to \(B\),
  2. the coefficient of restitution between the particle and the plane,
  3. the impulse exerted by the plane on the particle at \(A\).

Question 2(i):
AnswerMarks Guidance
AnswerMarks Guidance
Use of correct formulaM1 Or by energy
Vert speed imm before bounce \(= 2.8\ \text{ms}^{-1}\)A1
Time between bounces \(= 0.286\) (s) \((2/7)\)B1
[3]
Question 2(ii):
AnswerMarks Guidance
AnswerMarks Guidance
Use of their \(t\) in a correct formulaM1 Or \(-u = u - 9.8t\)
Vert speed imm after bounce \(= 1.4\ \text{ms}^{-1}\)A1
Coeff of rest \(= 0.5\)B1ft Their values for \(v\) after/\(v\) before; must be worked out to fraction or decimal; \(0 \leq e \leq 1\)
[3]
Question 2(iii):
AnswerMarks Guidance
AnswerMarks Guidance
\(\text{Imp} = \text{change of mom}\)M1 \(I = 0.3 \times (v) + 0.3 \times (u)\); allow their \(u, v\); allow sign errors for M1, allow if answer implies use of their values
\(I = 1.26\) (Ns)A1 CAO
[2]
## Question 2(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Use of correct formula | M1 | Or by energy |
| Vert speed imm before bounce $= 2.8\ \text{ms}^{-1}$ | A1 | |
| Time between bounces $= 0.286$ (s) $(2/7)$ | B1 | |
| **[3]** | | |

## Question 2(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Use of their $t$ in a correct formula | M1 | Or $-u = u - 9.8t$ |
| Vert speed imm after bounce $= 1.4\ \text{ms}^{-1}$ | A1 | |
| Coeff of rest $= 0.5$ | B1ft | Their values for $v$ after/$v$ before; must be worked out to fraction or decimal; $0 \leq e \leq 1$ |
| **[3]** | | |

## Question 2(iii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\text{Imp} = \text{change of mom}$ | M1 | $I = 0.3 \times (v) + 0.3 \times (u)$; allow their $u, v$; allow sign errors for M1, allow if answer implies use of their values |
| $I = 1.26$ (Ns) | A1 | CAO |
| **[2]** | | |
2 A particle of mass 0.3 kg is projected horizontally under gravity with velocity $3.5 \mathrm {~ms} ^ { - 1 }$ from a point 0.4 m above a smooth horizontal plane. The particle first hits the plane at point $A$; it bounces and hits the plane a second time at point $B$. The distance $A B$ is 1 m . Calculate\\
(i) the vertical component of the velocity of the particle when it arrives at $A$, and the time taken for the particle to travel from $A$ to $B$,\\
(ii) the coefficient of restitution between the particle and the plane,\\
(iii) the impulse exerted by the plane on the particle at $A$.

\hfill \mbox{\textit{OCR M3 2013 Q2 [8]}}