Standard +0.3 This is a straightforward equilibrium problem with elastic strings requiring application of Hooke's law to two strings and solving a single equation. The setup is clear, the method is standard (sum of tensions equals weight), and it involves routine algebraic manipulation with no conceptual subtleties or multi-step reasoning beyond the basic mechanics.
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\includegraphics[max width=\textwidth, alt={}, center]{3e8248ca-74f1-443f-a5db-d7da532d2815-2_435_665_255_699}
A small object \(W\) of weight 100 N is attached to one end of each of two parallel light elastic strings. One string is of natural length 0.4 m and has modulus of elasticity 20 N ; the other string is of natural length 0.6 m and has modulus of elasticity 30 N . The upper ends of both strings are attached to a horizontal ceiling and \(W\) hangs in equilibrium at a distance \(d \mathrm {~m}\) below the ceiling (see diagram). Find \(d\).
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\includegraphics[max width=\textwidth, alt={}, center]{3e8248ca-74f1-443f-a5db-d7da532d2815-2_435_665_255_699}
A small object $W$ of weight 100 N is attached to one end of each of two parallel light elastic strings. One string is of natural length 0.4 m and has modulus of elasticity 20 N ; the other string is of natural length 0.6 m and has modulus of elasticity 30 N . The upper ends of both strings are attached to a horizontal ceiling and $W$ hangs in equilibrium at a distance $d \mathrm {~m}$ below the ceiling (see diagram). Find $d$.
\hfill \mbox{\textit{OCR M3 2013 Q1 [5]}}