AQA M3 2013 June — Question 2 6 marks

Exam BoardAQA
ModuleM3 (Mechanics 3)
Year2013
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDimensional Analysis
TypeVerify dimensional consistency
DifficultyModerate -0.5 This is a straightforward dimensional analysis check requiring students to verify each term has dimensions of power (ML²T⁻³). While it involves multiple terms and careful tracking of dimensions, it's a routine application of a standard technique with no problem-solving insight required—easier than average but not trivial due to the algebraic manipulation needed.
Spec6.01a Dimensions: M, L, T notation6.01b Units vs dimensions: relationship6.01c Dimensional analysis: error checking

2 A car has mass \(m\) and travels up a slope which is inclined at an angle \(\theta\) to the horizontal. The car reaches a maximum speed \(v\) at a height \(h\) above its initial position. A constant resistance force \(R\) opposes the motion of the car, which has a maximum engine power output \(P\). Neda finds a formula for \(P\) as $$P = m g v \sin \theta + R v + \frac { 1 } { 2 } m v ^ { 3 } \frac { \sin \theta } { h }$$ where \(g\) is the acceleration due to gravity.
Given that the engine power output may be measured in newton metres per second, determine whether the formula is dimensionally consistent.

Question 2:
AnswerMarks Guidance
Working/AnswerMark Guidance
\([P] = \text{N m s}^{-1} = \text{kg m}^2 \text{s}^{-3}\)B1 Correct dimensions for power
\([mgv\sin\theta] = \text{kg} \cdot \text{m s}^{-2} \cdot \text{m s}^{-1} = \text{kg m}^2 \text{s}^{-3}\)M1 A1 Check first term
\([Rv] = \text{kg m s}^{-2} \cdot \text{m s}^{-1} = \text{kg m}^2 \text{s}^{-3}\)M1 A1 Check second term
\(\left[\frac{1}{2}mv^3\frac{\sin\theta}{h}\right] = \text{kg} \cdot (\text{m s}^{-1})^3 \cdot \text{m}^{-1} = \text{kg m}^2 \text{s}^{-3}\)M1 A1 Check third term
All three terms have same dimensions as \(P\), so formula is dimensionally consistentB1 Conclusion stated
# Question 2:

| Working/Answer | Mark | Guidance |
|---|---|---|
| $[P] = \text{N m s}^{-1} = \text{kg m}^2 \text{s}^{-3}$ | B1 | Correct dimensions for power |
| $[mgv\sin\theta] = \text{kg} \cdot \text{m s}^{-2} \cdot \text{m s}^{-1} = \text{kg m}^2 \text{s}^{-3}$ | M1 A1 | Check first term |
| $[Rv] = \text{kg m s}^{-2} \cdot \text{m s}^{-1} = \text{kg m}^2 \text{s}^{-3}$ | M1 A1 | Check second term |
| $\left[\frac{1}{2}mv^3\frac{\sin\theta}{h}\right] = \text{kg} \cdot (\text{m s}^{-1})^3 \cdot \text{m}^{-1} = \text{kg m}^2 \text{s}^{-3}$ | M1 A1 | Check third term |
| All three terms have same dimensions as $P$, so formula is dimensionally consistent | B1 | Conclusion stated |

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2 A car has mass $m$ and travels up a slope which is inclined at an angle $\theta$ to the horizontal. The car reaches a maximum speed $v$ at a height $h$ above its initial position. A constant resistance force $R$ opposes the motion of the car, which has a maximum engine power output $P$.

Neda finds a formula for $P$ as

$$P = m g v \sin \theta + R v + \frac { 1 } { 2 } m v ^ { 3 } \frac { \sin \theta } { h }$$

where $g$ is the acceleration due to gravity.\\
Given that the engine power output may be measured in newton metres per second, determine whether the formula is dimensionally consistent.

\hfill \mbox{\textit{AQA M3 2013 Q2 [6]}}