CAIE P3 2020 June — Question 10 11 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2020
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors: Lines & Planes
TypeLine intersection with line
DifficultyStandard +0.3 This is a straightforward multi-part vectors question requiring standard techniques: finding midpoint, dividing a line segment in a given ratio, forming line equations, finding intersection by equating parameters, and using dot product for angles. All steps are routine applications of A-level vector methods with no novel insight required, making it slightly easier than average.
Spec1.10c Magnitude and direction: of vectors1.10f Distance between points: using position vectors1.10h Vectors in kinematics: uniform acceleration in vector form

10 With respect to the origin \(O\), the points \(A\) and \(B\) have position vectors given by \(\overrightarrow { O A } = 6 \mathbf { i } + 2 \mathbf { j }\) and \(\overrightarrow { O B } = 2 \mathbf { i } + 2 \mathbf { j } + 3 \mathbf { k }\). The midpoint of \(O A\) is \(M\). The point \(N\) lying on \(A B\), between \(A\) and \(B\), is such that \(A N = 2 N B\).
  1. Find a vector equation for the line through \(M\) and \(N\).
    The line through \(M\) and \(N\) intersects the line through \(O\) and \(B\) at the point \(P\).
  2. Find the position vector of \(P\).
  3. Calculate angle \(O P M\), giving your answer in degrees.
    If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.

Question 10:
Part (a):
AnswerMarks Guidance
AnswerMark Guidance
State that the position vector of \(M\) is \(3\mathbf{i} + \mathbf{j}\)B1
Use a correct method to find the position vector of \(N\)M1
Obtain answer \(\dfrac{10}{3}\mathbf{i} + 2\mathbf{j} + 2\mathbf{k}\)A1
Use a correct method to form an equation for \(MN\)M1
Obtain correct answer in any form, e.g. \(\mathbf{r} = 3\mathbf{i} + \mathbf{j} + \lambda\!\left(\dfrac{1}{3}\mathbf{i} + \mathbf{j} + 2\mathbf{k}\right)\)A1
Total: 5 marks
Part (b):
AnswerMarks Guidance
AnswerMark Guidance
State or imply \(\mathbf{r} = \mu(2\mathbf{i} + 2\mathbf{j} + 3\mathbf{k})\) as equation for \(OB\)B1
Equate sufficient components of \(MN\) and \(OB\) and solve for \(\lambda\) or for \(\mu\)M1
Obtain \(\lambda = 3\) or \(\mu = 2\) and position vector \(4\mathbf{i} + 4\mathbf{j} + 6\mathbf{k}\) for \(P\)A1
Total: 3 marks
Part (c):
AnswerMarks Guidance
AnswerMark Guidance
Carry out correct process for evaluating the scalar product of direction vectors for \(OP\) and \(MP\), or equivalentM1
Using the correct process for the moduli, divide the scalar product by the product of the moduli and evaluate the inverse cosine of the resultM1
Obtain answer \(21.6°\)A1
Total: 3 marks
## Question 10:

### Part (a):

| Answer | Mark | Guidance |
|--------|------|----------|
| State that the position vector of $M$ is $3\mathbf{i} + \mathbf{j}$ | B1 | |
| Use a correct method to find the position vector of $N$ | M1 | |
| Obtain answer $\dfrac{10}{3}\mathbf{i} + 2\mathbf{j} + 2\mathbf{k}$ | A1 | |
| Use a correct method to form an equation for $MN$ | M1 | |
| Obtain correct answer in any form, e.g. $\mathbf{r} = 3\mathbf{i} + \mathbf{j} + \lambda\!\left(\dfrac{1}{3}\mathbf{i} + \mathbf{j} + 2\mathbf{k}\right)$ | A1 | |

**Total: 5 marks**

### Part (b):

| Answer | Mark | Guidance |
|--------|------|----------|
| State or imply $\mathbf{r} = \mu(2\mathbf{i} + 2\mathbf{j} + 3\mathbf{k})$ as equation for $OB$ | B1 | |
| Equate sufficient components of $MN$ and $OB$ and solve for $\lambda$ or for $\mu$ | M1 | |
| Obtain $\lambda = 3$ or $\mu = 2$ and position vector $4\mathbf{i} + 4\mathbf{j} + 6\mathbf{k}$ for $P$ | A1 | |

**Total: 3 marks**

### Part (c):

| Answer | Mark | Guidance |
|--------|------|----------|
| Carry out correct process for evaluating the scalar product of direction vectors for $OP$ and $MP$, or equivalent | M1 | |
| Using the correct process for the moduli, divide the scalar product by the product of the moduli and evaluate the inverse cosine of the result | M1 | |
| Obtain answer $21.6°$ | A1 | |

**Total: 3 marks**
10 With respect to the origin $O$, the points $A$ and $B$ have position vectors given by $\overrightarrow { O A } = 6 \mathbf { i } + 2 \mathbf { j }$ and $\overrightarrow { O B } = 2 \mathbf { i } + 2 \mathbf { j } + 3 \mathbf { k }$. The midpoint of $O A$ is $M$. The point $N$ lying on $A B$, between $A$ and $B$, is such that $A N = 2 N B$.
\begin{enumerate}[label=(\alph*)]
\item Find a vector equation for the line through $M$ and $N$.\\

The line through $M$ and $N$ intersects the line through $O$ and $B$ at the point $P$.
\item Find the position vector of $P$.
\item Calculate angle $O P M$, giving your answer in degrees.\\

If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2020 Q10 [11]}}