AQA M2 2013 June — Question 7 6 marks

Exam BoardAQA
ModuleM2 (Mechanics 2)
Year2013
SessionJune
Marks6
PaperDownload PDF ↗
TopicPower and driving force
TypeFind acceleration given power
DifficultyModerate -0.3 This is a straightforward application of the power-force-velocity relationship (P = Fv) to find driving force, followed by Newton's second law. It requires only two standard steps with no conceptual difficulty, making it slightly easier than average for A-level mechanics.
Spec6.02k Power: rate of doing work6.02l Power and velocity: P = Fv

7 A train, of mass 22 tonnes, moves along a straight horizontal track. A constant resistance force of 5000 N acts on the train. The power output of the engine of the train is 240 kW . Find the acceleration of the train when its speed is \(20 \mathrm {~ms} ^ { - 1 }\).

7 A train, of mass 22 tonnes, moves along a straight horizontal track. A constant resistance force of 5000 N acts on the train. The power output of the engine of the train is 240 kW .

Find the acceleration of the train when its speed is $20 \mathrm {~ms} ^ { - 1 }$.

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