| Exam Board | AQA |
|---|---|
| Module | M2 (Mechanics 2) |
| Year | 2013 |
| Session | June |
| Marks | 6 |
| Paper | Download PDF ↗ |
| Topic | Variable acceleration (1D) |
| Type | Velocity from displacement differentiation |
| Difficulty | Easy -1.2 This is a straightforward application of basic calculus (differentiate once for velocity, twice for acceleration) followed by F=ma. It requires only routine differentiation of a polynomial and substitution, with no problem-solving insight or multi-step reasoning beyond the standard mechanics procedure. |
| Spec | 3.02a Kinematics language: position, displacement, velocity, acceleration3.02f Non-uniform acceleration: using differentiation and integration3.03c Newton's second law: F=ma one dimension |
1 A particle, of mass 3 kg , moves along a straight line. At time $t$ seconds, the displacement, $s$ metres, of the particle from the origin is given by
$$s = 8 t ^ { 3 } + 15$$
\begin{enumerate}[label=(\alph*)]
\item Find the velocity of the particle at time $t$.
\item Find the magnitude of the resultant force acting on the particle when $t = 2$.
\end{enumerate}
\hfill \mbox{\textit{AQA M2 2013 Q1 [6]}}