AQA M2 2012 June — Question 7 7 marks

Exam BoardAQA
ModuleM2 (Mechanics 2)
Year2012
SessionJune
Marks7
PaperDownload PDF ↗
TopicDifferential equations
TypeParticle motion - velocity/time (dv/dt = f(v,t))
DifficultyStandard +0.3 This is a standard M2 differential equations question involving Newton's second law with resistance. Part (a) requires straightforward application of F=ma with given forces (2 marks suggests routine setup). Part (b) involves separating variables and integrating a simple linear DE—both are textbook exercises requiring method recall rather than problem-solving insight. Slightly above average difficulty due to the mechanics context and DE solving, but well within standard M2 scope.
Spec6.06a Variable force: dv/dt or v*dv/dx methods

7 A stone, of mass 5 kg , is projected vertically downwards, in a viscous liquid, with an initial speed of \(7 \mathrm {~ms} ^ { - 1 }\). At time \(t\) seconds after it is projected, the stone has speed \(v \mathrm {~ms} ^ { - 1 }\) and it experiences a resistance force of magnitude \(9.8 v\) newtons.
  1. When \(t \geqslant 0\), show that $$\frac { \mathrm { d } v } { \mathrm {~d} t } = - 1.96 ( v - 5 )$$ (2 marks)
  2. Find \(v\) in terms of \(t\).

7 A stone, of mass 5 kg , is projected vertically downwards, in a viscous liquid, with an initial speed of $7 \mathrm {~ms} ^ { - 1 }$.

At time $t$ seconds after it is projected, the stone has speed $v \mathrm {~ms} ^ { - 1 }$ and it experiences a resistance force of magnitude $9.8 v$ newtons.
\begin{enumerate}[label=(\alph*)]
\item When $t \geqslant 0$, show that

$$\frac { \mathrm { d } v } { \mathrm {~d} t } = - 1.96 ( v - 5 )$$

(2 marks)
\item Find $v$ in terms of $t$.
\end{enumerate}

\hfill \mbox{\textit{AQA M2 2012 Q7 [7]}}