| Exam Board | AQA |
|---|---|
| Module | M2 (Mechanics 2) |
| Year | 2012 |
| Session | June |
| Marks | 8 |
| Paper | Download PDF ↗ |
| Topic | Circular Motion 1 |
| Type | String through hole – hanging particle in equilibrium below table |
| Difficulty | Moderate -0.3 This is a standard M2 circular motion problem with coupled particles requiring straightforward application of T=mg for the hanging mass and T=mrω² for circular motion. The three parts are routine calculations once the tension is found, with no conceptual challenges beyond recognizing the equilibrium condition. |
| Spec | 6.05b Circular motion: v=r*omega and a=v^2/r |
5 Two particles, $A$ and $B$, are connected by a light inextensible string which passes through a hole in a smooth horizontal table. The edges of the hole are also smooth. Particle $A$, of mass 1.4 kg , moves, on the table, with constant speed in a circle of radius 0.3 m around the hole. Particle $B$, of mass 2.1 kg , hangs in equilibrium under the table, as shown in the diagram.\\
\includegraphics[max width=\textwidth, alt={}, center]{088327c1-acd3-486d-b76f-1fe2560ffaff-4_684_1022_1176_504}
\begin{enumerate}[label=(\alph*)]
\item Find the angular speed of particle $A$.
\item Find the speed of particle $A$.
\item Find the time taken for particle $A$ to complete one full circle around the hole.
\end{enumerate}
\hfill \mbox{\textit{AQA M2 2012 Q5 [8]}}