| Exam Board | AQA |
|---|---|
| Module | M2 (Mechanics 2) |
| Year | 2006 |
| Session | January |
| Marks | 7 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Circular Motion 1 |
| Type | Conical pendulum – horizontal circle in free space (no surface) |
| Difficulty | Moderate -0.8 This is a straightforward conical pendulum problem requiring standard resolution of forces (vertical equilibrium for tension, horizontal for centripetal force) and basic circular motion formula. All values are given, making it more routine than average with clear steps and no conceptual surprises. |
| Spec | 3.03f Weight: W=mg6.05b Circular motion: v=r*omega and a=v^2/r6.05c Horizontal circles: conical pendulum, banked tracks |
2 A particle, of mass 2 kg , is attached to one end of a light inextensible string. The other end is fixed to the point $O$. The particle is set into motion, so that it describes a horizontal circle of radius 0.6 metres, with the string at an angle of $30 ^ { \circ }$ to the vertical. The centre of the circle is vertically below $O$.\\
\includegraphics[max width=\textwidth, alt={}, center]{6a49fdd7-f180-451c-8f37-ad764fe13dfd-2_344_340_1418_842}
\begin{enumerate}[label=(\alph*)]
\item Show that the tension in the string is 22.6 N , correct to three significant figures.
\item Find the speed of the particle.
\end{enumerate}
\hfill \mbox{\textit{AQA M2 2006 Q2 [7]}}