| Exam Board | AQA |
|---|---|
| Module | M2 (Mechanics 2) |
| Year | 2006 |
| Session | January |
| Marks | 8 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Work done and energy |
| Type | Projectile energy - basic KE/PE calculation |
| Difficulty | Moderate -0.8 This is a straightforward application of energy conservation with standard formulas (KE = ½mv², PE = mgh). Part (a) is direct substitution, part (b) requires adding initial KE and PE lost, then working backwards to find speed. The 'show that' removes problem-solving difficulty, and the assumption (no air resistance) is standard. Easier than average A-level mechanics. |
| Spec | 6.02d Mechanical energy: KE and PE concepts6.02e Calculate KE and PE: using formulae6.02i Conservation of energy: mechanical energy principle |
1 A stone, of mass 0.4 kg , is thrown vertically upwards with a speed of $8 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ from a point at a height of 6 metres above ground level.
\begin{enumerate}[label=(\alph*)]
\item Calculate the initial kinetic energy of the stone.
\item \begin{enumerate}[label=(\roman*)]
\item Show that the kinetic energy of the stone when it hits the ground is 36.3 J , correct to three significant figures.
\item Hence find the speed at which the stone hits the ground.
\item State one assumption that you have made.
\end{enumerate}\end{enumerate}
\hfill \mbox{\textit{AQA M2 2006 Q1 [8]}}