Edexcel M1 — Question 4 10 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions
TypeCollision with two possible outcomes
DifficultyStandard +0.3 This is a standard M1 momentum conservation problem with straightforward application of the principle. Students must set up conservation equations for two scenarios, solve linear equations for the unknown mass, and calculate impulse using momentum change. While it requires careful attention to signs/directions and involves two parts, it's a routine textbook-style question with no novel problem-solving required—slightly easier than average due to its mechanical nature.
Spec6.03b Conservation of momentum: 1D two particles6.03f Impulse-momentum: relation

4. Two particles \(A\) and \(B\), of masses 50 grams and \(y\) grams, are moving in the same straight line, in opposite directions, with speeds \(7 \mathrm {~ms} ^ { - 1 }\) and \(4 \mathrm {~ms} ^ { - 1 }\) respectively, and collide. \includegraphics[max width=\textwidth, alt={}, center]{31efa627-5114-4797-9d46-7f1311c18ff8-1_218_508_2143_1382}
In each of the following separate cases, find the value of \(y\) and the magnitude of the impulse exerted by each particle on the other:
  1. after impact the particles move together with speed \(2.25 \mathrm {~ms} ^ { - 1 }\);
  2. after impact the particles move in opposite directions with speed \(5 \mathrm {~ms} ^ { - 1 }\). \section*{MECHANICS 1 (A) TEST PAPER 6 Page 2}

AnswerMarks Guidance
(a) Momentum: \(7 \times 50 - 4y = 2.25(50 + y)\)M1 A1 A1
\(6.25y = 237.5\)
\(y = 38\)
Impulse \(= 0.05(7 - 2.25) = 0.238\) NsM1 A1
(b) Momentum: \(7 \times 50 - 4y = -5 \times 50 + 5y\)M1 A1 A1
\(9y = 600\)
\(y = 66\frac{2}{3}\)
Impulse \(= 0.05 \times 12 = 0.6\) NsM1 A1 Total: 10 marks
**(a)** Momentum: $7 \times 50 - 4y = 2.25(50 + y)$ | M1 A1 A1 |
$6.25y = 237.5$ | |
$y = 38$ | |
Impulse $= 0.05(7 - 2.25) = 0.238$ Ns | M1 A1 |

**(b)** Momentum: $7 \times 50 - 4y = -5 \times 50 + 5y$ | M1 A1 A1 |
$9y = 600$ | |
$y = 66\frac{2}{3}$ | |
Impulse $= 0.05 \times 12 = 0.6$ Ns | M1 A1 | **Total: 10 marks**
4. Two particles $A$ and $B$, of masses 50 grams and $y$ grams, are moving in the same straight line, in opposite directions, with speeds $7 \mathrm {~ms} ^ { - 1 }$ and $4 \mathrm {~ms} ^ { - 1 }$ respectively, and collide.\\
\includegraphics[max width=\textwidth, alt={}, center]{31efa627-5114-4797-9d46-7f1311c18ff8-1_218_508_2143_1382}\\
In each of the following separate cases, find the value of $y$ and the magnitude of the impulse exerted by each particle on the other:
\begin{enumerate}[label=(\alph*)]
\item after impact the particles move together with speed $2.25 \mathrm {~ms} ^ { - 1 }$;
\item after impact the particles move in opposite directions with speed $5 \mathrm {~ms} ^ { - 1 }$.

\section*{MECHANICS 1 (A) TEST PAPER 6 Page 2}
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1  Q4 [10]}}