| Exam Board | AQA |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2012 |
| Session | June |
| Marks | 9 |
| Paper | Download PDF ↗ |
| Topic | Constant acceleration (SUVAT) |
| Type | SUVAT single equation: straightforward find |
| Difficulty | Moderate -0.3 This is a straightforward M1 mechanics question requiring standard SUVAT equations and F=ma. Part (a) involves routine kinematics calculations with clearly stated values, and part (b) is a simple one-mark adjustment accounting for air resistance. While it requires multiple steps, each is a direct application of standard formulas with no problem-solving insight needed, making it slightly easier than average. |
| Spec | 3.02d Constant acceleration: SUVAT formulae3.03c Newton's second law: F=ma one dimension3.03f Weight: W=mg |
3 A car is travelling at a speed of $20 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ along a straight horizontal road. The driver applies the brakes and a constant braking force acts on the car until it comes to rest.
\begin{enumerate}[label=(\alph*)]
\item Assume that no other horizontal forces act on the car.
\begin{enumerate}[label=(\roman*)]
\item After the car has travelled 75 metres, its speed has reduced to $10 \mathrm {~ms} ^ { - 1 }$. Find the acceleration of the car.
\item Find the time taken for the speed of the car to reduce from $20 \mathrm {~ms} ^ { - 1 }$ to zero.
\item Given that the mass of the car is 1400 kg , find the magnitude of the constant braking force.
\end{enumerate}\item Given that a constant air resistance force of magnitude 200 N acts on the car during the motion, find the magnitude of the constant braking force.\\
(1 mark)
\end{enumerate}
\hfill \mbox{\textit{AQA M1 2012 Q3 [9]}}