8 A particle is launched from the point \(A\) on a horizontal surface, with a velocity of \(22.4 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) at an angle \(\theta\) above the horizontal, as shown in the diagram.
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After 2 seconds, the particle reaches the point \(C\), where it is at its maximum height above the surface.
- Show that \(\sin \theta = 0.875\).
- Find the height of the point \(C\) above the horizontal surface.
- The particle returns to the surface at the point \(B\). Find the distance between \(A\) and \(B\). (3 marks)
- Find the length of time during which the height of the particle above the surface is greater than 5 metres.
- Find the minimum speed of the particle.