| Exam Board | AQA |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2011 |
| Session | June |
| Marks | 11 |
| Paper | Download PDF ↗ |
| Topic | Projectiles |
| Type | Horizontal projection from height |
| Difficulty | Moderate -0.8 This is a straightforward application of standard projectile motion equations with horizontal projection. All parts require direct substitution into SUVAT equations: (a) uses constant horizontal velocity, (b) uses s=ut+½at² vertically, (c) combines horizontal and vertical components with Pythagoras, (d) uses basic trigonometry. No problem-solving insight needed, just methodical application of memorized formulas. |
| Spec | 3.02d Constant acceleration: SUVAT formulae3.02h Motion under gravity: vector form3.02i Projectile motion: constant acceleration model |
6 A bullet is fired horizontally from the top of a vertical cliff, at a height of $h$ metres above the sea. It hits the sea 4 seconds after being fired, at a distance of 1000 metres from the base of the cliff, as shown in the diagram.\\
\includegraphics[max width=\textwidth, alt={}, center]{7ac7dfd0-4c3e-4eb7-920f-ce5b24ad1281-4_353_901_479_571}
\begin{enumerate}[label=(\alph*)]
\item Find the initial speed of the bullet.
\item $\quad$ Find $h$.
\item Find the speed of the bullet when it hits the sea.
\item Find the angle between the velocity of the bullet and the horizontal when it hits the sea.
\end{enumerate}
\hfill \mbox{\textit{AQA M1 2011 Q6 [11]}}