| Exam Board | AQA |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2011 |
| Session | June |
| Marks | 8 |
| Paper | Download PDF ↗ |
| Topic | Constant acceleration (SUVAT) |
| Type | SUVAT single equation: straightforward find |
| Difficulty | Moderate -0.8 This is a straightforward SUVAT kinematics problem followed by a basic Newton's second law application. Part (a) requires direct application of v²=u²+2as (with the answer given), then v=u+at. Part (b) is a standard vertical forces problem: T - mg = ma. All steps are routine textbook exercises requiring only recall and substitution, making it easier than average. |
| Spec | 3.02d Constant acceleration: SUVAT formulae3.03c Newton's second law: F=ma one dimension |
1 A crane is used to lift a load, using a single vertical cable which is attached to the load. The load accelerates uniformly from rest. When it has risen 0.9 metres, its speed is $0.6 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.
\begin{enumerate}[label=(\alph*)]
\item \begin{enumerate}[label=(\roman*)]
\item Show that the acceleration of the load is $0.2 \mathrm {~m} \mathrm {~s} ^ { - 2 }$.
\item Find the time taken for the load to rise 0.9 metres.
\end{enumerate}\item Given that the mass of the load is 800 kg , find the tension in the cable while the load is accelerating.
\end{enumerate}
\hfill \mbox{\textit{AQA M1 2011 Q1 [8]}}