AQA M1 2006 June — Question 8 8 marks

Exam BoardAQA
ModuleM1 (Mechanics 1)
Year2006
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions
TypeCollision with vector velocities
DifficultyModerate -0.3 This is a straightforward momentum conservation problem with vector notation. Part (a) requires simple vector addition of momenta (mass × velocity). Part (b) applies conservation of momentum in two dimensions to find m and k. While it involves vectors and two components, the steps are routine and mechanical—no geometric insight or novel problem-solving is needed, making it slightly easier than average.
Spec1.02c Simultaneous equations: two variables by elimination and substitution6.03b Conservation of momentum: 1D two particles

8 Two particles, \(A\) and \(B\), are moving on a smooth horizontal surface.
The particle \(A\) has mass \(m \mathrm {~kg}\) and is moving with velocity \(\left[ \begin{array} { r } 5 \\ - 3 \end{array} \right] \mathrm { ms } ^ { - 1 }\). The particle \(B\) has mass 0.2 kg and is moving with velocity \(\left[ \begin{array} { l } 2 \\ 3 \end{array} \right] \mathrm { ms } ^ { - 1 }\).
  1. Find, in terms of \(m\), an expression for the total momentum of the particles.
  2. The particles \(A\) and \(B\) collide and form a single particle \(C\), which moves with velocity \(\left[ \begin{array} { c } k \\ 1 \end{array} \right] \mathrm { m } \mathrm { s } ^ { - 1 }\), where \(k\) is a constant.
    1. Show that \(m = 0.1\).
    2. Find the value of \(k\).

Question 8:
Part (a)
AnswerMarks Guidance
WorkingMarks Guidance
\(m(5\mathbf{i} - 3\mathbf{j}) + 0.2(2\mathbf{i} + 3\mathbf{j})\)M1 Momentum terms added
A1All correct Total: 2
Part (b)(i)
AnswerMarks Guidance
WorkingMarks Guidance
\((0.2 + m)(k\mathbf{i} + \mathbf{j})\)B1 Seen or used to find \(m\)
Use of conservation of momentumM1 Used with candidate's expressions in 2D equation or used to give one of the 1D equations below
\(-3m + 0.6 = 0.2 + m\)
\(m = 0.1\)A1 Full verification accepted, CAO
Part (b)(ii)
AnswerMarks Guidance
WorkingMarks Guidance
\(5m + 0.4 = 0.2k + mk\)A1
substitute \(m\)m1
\(k = 3\)A1
## Question 8:

### Part (a)
| Working | Marks | Guidance |
|---------|-------|----------|
| $m(5\mathbf{i} - 3\mathbf{j}) + 0.2(2\mathbf{i} + 3\mathbf{j})$ | M1 | Momentum terms added |
| | A1 | All correct | **Total: 2** |

### Part (b)(i)
| Working | Marks | Guidance |
|---------|-------|----------|
| $(0.2 + m)(k\mathbf{i} + \mathbf{j})$ | B1 | Seen or used to find $m$ |
| Use of conservation of momentum | M1 | Used with candidate's expressions in 2D equation or used to give one of the 1D equations below |
| $-3m + 0.6 = 0.2 + m$ | | |
| $m = 0.1$ | A1 | Full verification accepted, CAO | **Total: 3** |

### Part (b)(ii)
| Working | Marks | Guidance |
|---------|-------|----------|
| $5m + 0.4 = 0.2k + mk$ | A1 | |
| substitute $m$ | m1 | |
| $k = 3$ | A1 | | **Total: 3** |
8 Two particles, $A$ and $B$, are moving on a smooth horizontal surface.\\
The particle $A$ has mass $m \mathrm {~kg}$ and is moving with velocity $\left[ \begin{array} { r } 5 \\ - 3 \end{array} \right] \mathrm { ms } ^ { - 1 }$.

The particle $B$ has mass 0.2 kg and is moving with velocity $\left[ \begin{array} { l } 2 \\ 3 \end{array} \right] \mathrm { ms } ^ { - 1 }$.
\begin{enumerate}[label=(\alph*)]
\item Find, in terms of $m$, an expression for the total momentum of the particles.
\item The particles $A$ and $B$ collide and form a single particle $C$, which moves with velocity $\left[ \begin{array} { c } k \\ 1 \end{array} \right] \mathrm { m } \mathrm { s } ^ { - 1 }$, where $k$ is a constant.
\begin{enumerate}[label=(\roman*)]
\item Show that $m = 0.1$.
\item Find the value of $k$.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{AQA M1 2006 Q8 [8]}}