AQA M1 2011 January — Question 3 13 marks

Exam BoardAQA
ModuleM1 (Mechanics 1)
Year2011
SessionJanuary
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPulley systems
TypeHorizontal road towing
DifficultyModerate -0.8 This is a straightforward M1 mechanics question requiring standard application of Newton's second law to a two-body system. Part (a) involves basic F=ma calculations with given values, part (b) uses elementary kinematics (v=u+at, s=ut+½at²), and part (c) asks for a simple conceptual explanation. All techniques are routine with no problem-solving insight required, making it easier than average.
Spec3.02d Constant acceleration: SUVAT formulae3.03c Newton's second law: F=ma one dimension3.03d Newton's second law: 2D vectors3.03k Connected particles: pulleys and equilibrium

3 A car, of mass 1200 kg , tows a caravan, of mass 1000 kg , along a straight horizontal road. The caravan is attached to the car by a horizontal tow bar, as shown in the diagram. \includegraphics[max width=\textwidth, alt={}, center]{f30b02da-a41e-44cb-b45f-9e6a3a9d0528-06_277_901_484_584} Assume that a constant resistance force of magnitude 200 newtons acts on the car and a constant resistance force of magnitude 300 newtons acts on the caravan. A constant driving force of magnitude \(P\) newtons acts on the car in the direction of motion. The car and caravan accelerate at \(0.8 \mathrm {~ms} ^ { - 2 }\).
    1. Find \(P\).
    2. Find the magnitude of the force in the tow bar that connects the car to the caravan.
    1. Find the time that it takes for the speed of the car and caravan to increase from \(7 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) to \(15 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
    2. Find the distance that they travel in this time.
  1. Explain why the assumption that the resistance forces are constant is unrealistic.
    (1 mark)

Question 3:
Part (a)(i):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Newton's 2nd law for whole system: \(P - 200 - 300 = (1200 + 1000) \times 0.8\)M1 A1 Correct equation with all terms
\(P - 500 = 1760\)A1
\(P = 2260 \text{ N}\)A1
Part (a)(ii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Apply Newton's 2nd law to caravan: \(T - 300 = 1000 \times 0.8\)M1 A1 Equation for caravan only
\(T = 300 + 800 = 1100 \text{ N}\)A1
Part (b)(i):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(v = u + at \Rightarrow 15 = 7 + 0.8t\)M1 A1 Correct use of suvat
\(t = \frac{8}{0.8} = 10 \text{ s}\)A1
Part (b)(ii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(s = ut + \frac{1}{2}at^2 = 7\times10 + \frac{1}{2}\times0.8\times100\)M1 A1 Or other valid suvat method
\(s = 70 + 40 = 110 \text{ m}\)A1
Part (c):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Resistance forces vary with speed (e.g. air resistance increases as speed increases)B1 Accept equivalent correct physical reasoning
# Question 3:

## Part (a)(i):
| Answer/Working | Marks | Guidance |
|---|---|---|
| Newton's 2nd law for whole system: $P - 200 - 300 = (1200 + 1000) \times 0.8$ | M1 A1 | Correct equation with all terms |
| $P - 500 = 1760$ | A1 | |
| $P = 2260 \text{ N}$ | A1 | |

## Part (a)(ii):
| Answer/Working | Marks | Guidance |
|---|---|---|
| Apply Newton's 2nd law to caravan: $T - 300 = 1000 \times 0.8$ | M1 A1 | Equation for caravan only |
| $T = 300 + 800 = 1100 \text{ N}$ | A1 | |

## Part (b)(i):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $v = u + at \Rightarrow 15 = 7 + 0.8t$ | M1 A1 | Correct use of suvat |
| $t = \frac{8}{0.8} = 10 \text{ s}$ | A1 | |

## Part (b)(ii):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $s = ut + \frac{1}{2}at^2 = 7\times10 + \frac{1}{2}\times0.8\times100$ | M1 A1 | Or other valid suvat method |
| $s = 70 + 40 = 110 \text{ m}$ | A1 | |

## Part (c):
| Answer/Working | Marks | Guidance |
|---|---|---|
| Resistance forces vary with speed (e.g. air resistance increases as speed increases) | B1 | Accept equivalent correct physical reasoning |
3 A car, of mass 1200 kg , tows a caravan, of mass 1000 kg , along a straight horizontal road. The caravan is attached to the car by a horizontal tow bar, as shown in the diagram.\\
\includegraphics[max width=\textwidth, alt={}, center]{f30b02da-a41e-44cb-b45f-9e6a3a9d0528-06_277_901_484_584}

Assume that a constant resistance force of magnitude 200 newtons acts on the car and a constant resistance force of magnitude 300 newtons acts on the caravan. A constant driving force of magnitude $P$ newtons acts on the car in the direction of motion. The car and caravan accelerate at $0.8 \mathrm {~ms} ^ { - 2 }$.
\begin{enumerate}[label=(\alph*)]
\item \begin{enumerate}[label=(\roman*)]
\item Find $P$.
\item Find the magnitude of the force in the tow bar that connects the car to the caravan.
\end{enumerate}\item \begin{enumerate}[label=(\roman*)]
\item Find the time that it takes for the speed of the car and caravan to increase from $7 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ to $15 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.
\item Find the distance that they travel in this time.
\end{enumerate}\item Explain why the assumption that the resistance forces are constant is unrealistic.\\
(1 mark)
\end{enumerate}

\hfill \mbox{\textit{AQA M1 2011 Q3 [13]}}