Edexcel S2 — Question 7 16 marks

Exam BoardEdexcel
ModuleS2 (Statistics 2)
Marks16
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicContinuous Probability Distributions and Random Variables
TypeFind median or percentiles
DifficultyStandard +0.8 This S2 question requires multiple skills: verifying the pdf integrates to 1 (involving piecewise integration), finding the median (solving a quadratic equation from cumulative distribution), sketching a piecewise function, and critically evaluating a statistical model. While each component is standard S2 material, the combination of techniques and the need for statistical reasoning about model validity makes this moderately challenging, above average difficulty.
Spec5.03a Continuous random variables: pdf and cdf5.03b Solve problems: using pdf5.03f Relate pdf-cdf: medians and percentiles

7. The time, in hours, taken to run the London marathon is modelled by a continuous random variable \(T\) with the probability density function $$f ( t ) = \begin{cases} c ( t - 2 ) & 2 \leq t < 4 \\ \frac { 2 c ( 7 - t ) } { 3 } & 4 \leq t \leq 7 \\ 0 & \text { otherwise } \end{cases}$$
  1. Sketch the function \(\mathrm { f } ( t )\), and show that \(c = \frac { 1 } { 5 }\).
  2. Calculate the median value of \(T\).
  3. Make two critical comments about the model.

AnswerMarks
(a) Graph sketched: \(\frac{1}{2} \times 2c \times 5 = 1\), so \(c = \frac{1}{5}\)B3 M1 A1
(b) Median \(m\) has \(P(4 < X < m) = \frac{1}{2} - \frac{2}{5} = \frac{1}{10}\)M1 A1
\(\frac{2}{15}\int_m^7 t-1 \, dt = \frac{1}{10}\) leading to \(7m - \frac{1}{2}m^2 - 20 = \frac{3}{4}\)M1 A1 M1 A1
\(2m^2 - 28m + 83 = 0\), so \(m = 4.26\)A1 M1 A1
(c) Sections of graph will not be precise straight lines in reality; some people will take longer than 7 hoursB1; B1
Total: 16 marks
(a) Graph sketched: $\frac{1}{2} \times 2c \times 5 = 1$, so $c = \frac{1}{5}$ | B3 M1 A1 |

(b) Median $m$ has $P(4 < X < m) = \frac{1}{2} - \frac{2}{5} = \frac{1}{10}$ | M1 A1 |

$\frac{2}{15}\int_m^7 t-1 \, dt = \frac{1}{10}$ leading to $7m - \frac{1}{2}m^2 - 20 = \frac{3}{4}$ | M1 A1 M1 A1 |

$2m^2 - 28m + 83 = 0$, so $m = 4.26$ | A1 M1 A1 |

(c) Sections of graph will not be precise straight lines in reality; some people will take longer than 7 hours | B1; B1 |

**Total: 16 marks**
7. The time, in hours, taken to run the London marathon is modelled by a continuous random variable $T$ with the probability density function

$$f ( t ) = \begin{cases} c ( t - 2 ) & 2 \leq t < 4 \\ \frac { 2 c ( 7 - t ) } { 3 } & 4 \leq t \leq 7 \\ 0 & \text { otherwise } \end{cases}$$
\begin{enumerate}[label=(\alph*)]
\item Sketch the function $\mathrm { f } ( t )$, and show that $c = \frac { 1 } { 5 }$.
\item Calculate the median value of $T$.
\item Make two critical comments about the model.
\end{enumerate}

\hfill \mbox{\textit{Edexcel S2  Q7 [16]}}