# Question 2:

## Part (a)(i)

| Answer | Mark | Guidance |
|--------|------|----------|
| $P(X = 421) = 0$ | B1 | Since $X$ is continuous |

## Part (a)(ii)

| Answer | Mark | Guidance |
|--------|------|----------|
| $P(X < 425) = P\left(Z < \frac{425-421}{2.5}\right) = P(Z < 1.6)$ | M1 | Standardising correctly |
| $= 0.9452$ | A1 | |

## Part (a)(iii)

| Answer | Mark | Guidance |
|--------|------|----------|
| $P(418 < X < 424) = P\left(\frac{418-421}{2.5} < Z < \frac{424-421}{2.5}\right)$ | M1 | Standardising both values |
| $= P(-1.2 < Z < 1.2)$ | A1 | |
| $= 2(0.8849) - 1 = 0.7698 \approx 0.770$ | A1 | |

## Part (b)

| Answer | Mark | Guidance |
|--------|------|----------|
| $P(X < x) = 0.98 \Rightarrow \frac{x - 421}{2.5} = 2.054$ | M1 | Using inverse normal, $z = 2.054$ |
| A1 | Correct $z$ value |
| $x = 421 + 2.5 \times 2.054 = 426.1$ | A1 | |

## Part (c)

| Answer | Mark | Guidance |
|--------|------|----------|
| $P(Y < 410) = 0.01 \Rightarrow \frac{410 - \mu}{3} = -2.3263$ | M1 | Setting up equation with correct $z$ value |
| A1 | $z = -2.3263$ (or $\pm 2.326$) |
| $\mu = 410 + 3 \times 2.3263 = 416.979 \approx 417.0$ | M1 | Correct equation for $\mu$ |
| A1 | |

I can see these are answer space pages (blank lined pages for students to write their answers) for Questions 2 and 3 of what appears to be an AQA Statistics exam paper. These pages do not contain any mark scheme content - they are simply blank answer spaces.

The question content visible is for **Question 3**, which involves binomial distributions for an auction house scenario. However, no mark scheme is shown in these images.

To get the mark scheme content you're looking for, you would need to provide images of the **actual mark scheme document**, which is a separate publication from the question paper. The pages shown here are from the **question paper** (specifically the answer booklet pages), not the mark scheme.

If you can provide images of the mark scheme document, I would be happy to extract and format that content for you.