Edexcel C3 — Question 7 12 marks

Exam BoardEdexcel
ModuleC3 (Core Mathematics 3)
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComposite & Inverse Functions
TypeFind inverse function
DifficultyStandard +0.3 This is a standard C3 inverse function question with multiple routine parts: completing the square (basic), stating range (direct consequence), finding inverse (standard technique), describing transformations (straightforward), and finding a normal (requires derivative of inverse but follows standard method). While multi-part with 5 sections, each component uses well-practiced techniques without requiring novel insight, making it slightly easier than average overall.
Spec1.02e Complete the square: quadratic polynomials and turning points1.02v Inverse and composite functions: graphs and conditions for existence1.02w Graph transformations: simple transformations of f(x)1.07m Tangents and normals: gradient and equations

7. \(\quad f ( x ) = x ^ { 2 } - 2 x + 5 , x \in \mathbb { R } , x \geq 1\).
  1. Express \(\mathrm { f } ( x )\) in the form \(( x + a ) ^ { 2 } + b\), where \(a\) and \(b\) are constants.
  2. State the range of f.
  3. Find an expression for \(\mathrm { f } ^ { - 1 } ( x )\).
  4. Describe fully two transformations that would map the graph of \(y = \mathrm { f } ^ { - 1 } ( x )\) onto the graph of \(y = \sqrt { x } , x \geq 0\).
  5. Find an equation for the normal to the curve \(y = \mathrm { f } ^ { - 1 } ( x )\) at the point where \(x = 8\).

AnswerMarks
(a) \(f(x) = (x-1)^2-1+5 = (x-1)^2+4\)M1 A1
(b) \(f(x) \geq 4\)B1
(c) \(y = (x-1)^2+4\)
\((x-1)^2 = y-4\)
AnswerMarks
\(x-1 = \pm\sqrt{y-4}\)M1
\(x = 1 \pm \sqrt{y-4}\)
AnswerMarks
\(f^{-1}(x) = 1+\sqrt{x-4}\)M1 A1
(d) Translation by 4 units in negative \(x\) direction
AnswerMarks
Translation by 1 unit in negative \(y\) direction (either first)B2
(e) \(\frac{dy}{dx} = \frac{1}{2}(x-4)^{-\frac{1}{2}}\)M1
\(x = 8, y = 3\), grad \(= \frac{1}{2}\)A1
\(\therefore\) grad of normal \(= -4\)
AnswerMarks Guidance
\(\therefore y-3 = -4(x-8)\)[\(y = 35-4x\)] M1 A1
**(a)** $f(x) = (x-1)^2-1+5 = (x-1)^2+4$ | M1 A1

**(b)** $f(x) \geq 4$ | B1

**(c)** $y = (x-1)^2+4$

$(x-1)^2 = y-4$

$x-1 = \pm\sqrt{y-4}$ | M1

$x = 1 \pm \sqrt{y-4}$

$f^{-1}(x) = 1+\sqrt{x-4}$ | M1 A1

**(d)** Translation by 4 units in negative $x$ direction
Translation by 1 unit in negative $y$ direction (either first) | B2

**(e)** $\frac{dy}{dx} = \frac{1}{2}(x-4)^{-\frac{1}{2}}$ | M1

$x = 8, y = 3$, grad $= \frac{1}{2}$ | A1

$\therefore$ grad of normal $= -4$

$\therefore y-3 = -4(x-8)$ | [$y = 35-4x$] | M1 A1 | **(12)**
7. $\quad f ( x ) = x ^ { 2 } - 2 x + 5 , x \in \mathbb { R } , x \geq 1$.
\begin{enumerate}[label=(\alph*)]
\item Express $\mathrm { f } ( x )$ in the form $( x + a ) ^ { 2 } + b$, where $a$ and $b$ are constants.
\item State the range of f.
\item Find an expression for $\mathrm { f } ^ { - 1 } ( x )$.
\item Describe fully two transformations that would map the graph of $y = \mathrm { f } ^ { - 1 } ( x )$ onto the graph of $y = \sqrt { x } , x \geq 0$.
\item Find an equation for the normal to the curve $y = \mathrm { f } ^ { - 1 } ( x )$ at the point where $x = 8$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C3  Q7 [12]}}