Edexcel C3 — Question 5 10 marks

Exam BoardEdexcel
ModuleC3 (Core Mathematics 3)
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Equations & Modelling
TypeFinding x from given y value
DifficultyModerate -0.3 This is a standard exponential modelling question requiring routine application of logarithms to find k, then straightforward substitution and differentiation. All three parts follow predictable patterns typical of C3 exponential growth questions, making it slightly easier than average but still requiring multiple techniques.
Spec1.06i Exponential growth/decay: in modelling context1.07k Differentiate trig: sin(kx), cos(kx), tan(kx)

5. The number of bacteria present in a culture at time \(t\) hours is modelled by the continuous variable \(N\) and the relationship $$N = 2000 \mathrm { e } ^ { k t } ,$$ where \(k\) is a constant. Given that when \(t = 3 , N = 18000\), find
  1. the value of \(k\) to 3 significant figures,
  2. how long it takes for the number of bacteria present to double, giving your answer to the nearest minute,
  3. the rate at which the number of bacteria is increasing when \(t = 3\).

(a) \(t = 3, N = 18000 \Rightarrow 18000 = 2000e^{3k}\), \(e^{3k} = 9\)
AnswerMarks
\(k = \frac{1}{3}\ln 9 = 0.732\) (3sf)M1 M1 A1
(b) \(4000 = 2000e^{0.7324t}\)M1
\(t = \frac{\ln 2}{0.7324} \ln 2 = 0.9464\) hours
AnswerMarks Guidance
\(\therefore\) doubles in 57 minutes (nearest minute)M1 A1
(c) \(N = 2000e^{0.7324t}\), \(\frac{dN}{dt} = 0.7324 \times 2000e^{0.7324t} = 1465e^{0.7324t}\)M1 A1
When \(t = 3\), \(\frac{dN}{dt} = 13200 \therefore\) increasing at rate of 13200 per hour (3sf)A1 (10)
**(a)** $t = 3, N = 18000 \Rightarrow 18000 = 2000e^{3k}$, $e^{3k} = 9$

$k = \frac{1}{3}\ln 9 = 0.732$ (3sf) | M1 M1 A1

**(b)** $4000 = 2000e^{0.7324t}$ | M1

$t = \frac{\ln 2}{0.7324} \ln 2 = 0.9464$ hours

$\therefore$ doubles in 57 minutes (nearest minute) | M1 A1

**(c)** $N = 2000e^{0.7324t}$, $\frac{dN}{dt} = 0.7324 \times 2000e^{0.7324t} = 1465e^{0.7324t}$ | M1 A1

When $t = 3$, $\frac{dN}{dt} = 13200 \therefore$ increasing at rate of 13200 per hour (3sf) | A1 | **(10)**
5. The number of bacteria present in a culture at time $t$ hours is modelled by the continuous variable $N$ and the relationship

$$N = 2000 \mathrm { e } ^ { k t } ,$$

where $k$ is a constant.

Given that when $t = 3 , N = 18000$, find
\begin{enumerate}[label=(\alph*)]
\item the value of $k$ to 3 significant figures,
\item how long it takes for the number of bacteria present to double, giving your answer to the nearest minute,
\item the rate at which the number of bacteria is increasing when $t = 3$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C3  Q5 [10]}}