AQA C3 2009 June — Question 6 19 marks

Exam BoardAQA
ModuleC3 (Core Mathematics 3)
Year2009
SessionJune
Marks19
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVolumes of Revolution
TypeRotation about y-axis, standard curve
DifficultyStandard +0.3 This is a multi-part question covering standard C3 techniques: volume of revolution about y-axis (requiring rearrangement to x in terms of y), mid-ordinate rule numerical integration, differentiation of a surd function, and combining results to find an area. While it has multiple parts (7 marks total), each component is routine application of standard methods with no novel problem-solving required. The volume of revolution is slightly more challenging than x-axis rotation but still follows a standard formula, making this slightly easier than average overall.
Spec1.07i Differentiate x^n: for rational n and sums1.07m Tangents and normals: gradient and equations1.09f Trapezium rule: numerical integration4.08d Volumes of revolution: about x and y axes

6 The diagram shows the curve with equation \(y = \sqrt { 100 - 4 x ^ { 2 } }\), where \(x \geqslant 0\). \includegraphics[max width=\textwidth, alt={}, center]{a596af76-9680-4ccb-a512-5b2575414429-5_518_494_367_758}
  1. Calculate the volume of the solid generated when the region bounded by the curve shown above and the coordinate axes is rotated through \(360 ^ { \circ }\) about the \(\boldsymbol { y }\)-axis, giving your answer in terms of \(\pi\).
  2. Use the mid-ordinate rule with five strips of equal width to find an estimate for \(\int _ { 0 } ^ { 5 } \sqrt { 100 - 4 x ^ { 2 } } \mathrm {~d} x\), giving your answer to three significant figures.
  3. The point \(P\) on the curve has coordinates \(( 3,8 )\).
    1. Find the gradient of the curve \(y = \sqrt { 100 - 4 x ^ { 2 } }\) at the point \(P\).
    2. Hence show that the equation of the tangent to the curve at the point \(P\) can be written as \(2 y + 3 x = 25\).
  4. The shaded regions on the diagram below are bounded by the curve, the tangent at \(P\) and the coordinate axes. \includegraphics[max width=\textwidth, alt={}, center]{a596af76-9680-4ccb-a512-5b2575414429-5_642_546_1800_731} Use your answers to part (b) and part (c)(ii) to find an approximate value for the total area of the shaded regions. Give your answer to three significant figures.

6 The diagram shows the curve with equation $y = \sqrt { 100 - 4 x ^ { 2 } }$, where $x \geqslant 0$.\\
\includegraphics[max width=\textwidth, alt={}, center]{a596af76-9680-4ccb-a512-5b2575414429-5_518_494_367_758}
\begin{enumerate}[label=(\alph*)]
\item Calculate the volume of the solid generated when the region bounded by the curve shown above and the coordinate axes is rotated through $360 ^ { \circ }$ about the $\boldsymbol { y }$-axis, giving your answer in terms of $\pi$.
\item Use the mid-ordinate rule with five strips of equal width to find an estimate for $\int _ { 0 } ^ { 5 } \sqrt { 100 - 4 x ^ { 2 } } \mathrm {~d} x$, giving your answer to three significant figures.
\item The point $P$ on the curve has coordinates $( 3,8 )$.
\begin{enumerate}[label=(\roman*)]
\item Find the gradient of the curve $y = \sqrt { 100 - 4 x ^ { 2 } }$ at the point $P$.
\item Hence show that the equation of the tangent to the curve at the point $P$ can be written as $2 y + 3 x = 25$.
\end{enumerate}\item The shaded regions on the diagram below are bounded by the curve, the tangent at $P$ and the coordinate axes.\\
\includegraphics[max width=\textwidth, alt={}, center]{a596af76-9680-4ccb-a512-5b2575414429-5_642_546_1800_731}

Use your answers to part (b) and part (c)(ii) to find an approximate value for the total area of the shaded regions. Give your answer to three significant figures.
\end{enumerate}

\hfill \mbox{\textit{AQA C3 2009 Q6 [19]}}