AQA C3 2009 June — Question 3 8 marks

Exam BoardAQA
ModuleC3 (Core Mathematics 3)
Year2009
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard trigonometric equations
TypeEquation with 'show that' rewriting preliminary part
DifficultyModerate -0.3 This is a standard C3 trigonometric equation question with routine steps: (a) is basic calculator work, (b) uses the standard identity sec²x = 1 + tan²x requiring simple algebraic manipulation, and (c) applies the quadratic formula to solve for tan x then finds angles. All techniques are textbook exercises with no novel problem-solving required, making it slightly easier than average.
Spec1.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^21.05o Trigonometric equations: solve in given intervals

3
  1. Solve the equation \(\tan x = - \frac { 1 } { 3 }\), giving all the values of \(x\) in the interval \(0 < x < 2 \pi\) in radians to two decimal places.
  2. Show that the equation $$3 \sec ^ { 2 } x = 5 ( \tan x + 1 )$$ can be written in the form \(3 \tan ^ { 2 } x - 5 \tan x - 2 = 0\).
  3. Hence, or otherwise, solve the equation $$3 \sec ^ { 2 } x = 5 ( \tan x + 1 )$$ giving all the values of \(x\) in the interval \(0 < x < 2 \pi\) in radians to two decimal places.
    (4 marks)

3
\begin{enumerate}[label=(\alph*)]
\item Solve the equation $\tan x = - \frac { 1 } { 3 }$, giving all the values of $x$ in the interval $0 < x < 2 \pi$ in radians to two decimal places.
\item Show that the equation

$$3 \sec ^ { 2 } x = 5 ( \tan x + 1 )$$

can be written in the form $3 \tan ^ { 2 } x - 5 \tan x - 2 = 0$.
\item Hence, or otherwise, solve the equation

$$3 \sec ^ { 2 } x = 5 ( \tan x + 1 )$$

giving all the values of $x$ in the interval $0 < x < 2 \pi$ in radians to two decimal places.\\
(4 marks)
\end{enumerate}

\hfill \mbox{\textit{AQA C3 2009 Q3 [8]}}