2 At the point \(( x , y )\) on a curve, where \(x > 0\), the gradient is given by
$$\frac { \mathrm { d } y } { \mathrm {~d} x } = 7 \sqrt { x ^ { 5 } } - 4$$
- Write \(\sqrt { x ^ { 5 } }\) in the form \(x ^ { k }\), where \(k\) is a fraction.
- Find \(\int \left( 7 \sqrt { x ^ { 5 } } - 4 \right) \mathrm { d } x\).
- Hence find the equation of the curve, given that the curve passes through the point \(( 1,3 )\).