AQA C2 2008 January — Question 1 6 marks

Exam BoardAQA
ModuleC2 (Core Mathematics 2)
Year2008
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRadians, Arc Length and Sector Area
TypeSector area calculation
DifficultyModerate -0.8 This is a straightforward sector area question requiring only the formula A = ½r²θ and basic algebraic manipulation. Part (a) involves setting up and solving a simple equation (18 = 2 × ½ × 36 × θ), while part (b) requires adding arc length to two radii using s = rθ. Both parts are routine applications of standard formulas with no problem-solving insight needed, making this easier than average for A-level.
Spec1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta

1 The diagrams show a rectangle of length 6 cm and width 3 cm , and a sector of a circle of radius 6 cm and angle \(\theta\) radians. \includegraphics[max width=\textwidth, alt={}, center]{14c2acbb-5f3e-40e2-8b88-162341ab9f71-2_266_1128_589_424} The area of the rectangle is twice the area of the sector.
  1. Show that \(\theta = 0.5\).
  2. Find the perimeter of the sector.

Question 1:
Part (a)
AnswerMarks Guidance
WorkingMark Guidance
Area of sector \(= \frac{1}{2}r^2\theta = \frac{1}{2}\times 6^2 \times \theta\)M1 \(\frac{1}{2}r^2\theta\) seen or used
\(6\times 3 = 2\times\frac{1}{2}\times 6^2\times\theta\)m1 OE Forming equation
\(36\theta = 18 \Rightarrow \theta = 0.5\)A1 AG — Total: 3
Part (b)
AnswerMarks Guidance
WorkingMark Guidance
Arc \(= 6\theta\)M1 \(r\theta\) seen or used
\(\ldots = 3\) cmA1 PI by a correct perimeter
\(\Rightarrow\) Perimeter \(= 12 +\) arc \(= 15\) cmA1F Ft wrong evaluation of \(6\theta\). Condone missing/wrong units — Total: 3
## Question 1:

### Part (a)
| Working | Mark | Guidance |
|---------|------|----------|
| Area of sector $= \frac{1}{2}r^2\theta = \frac{1}{2}\times 6^2 \times \theta$ | M1 | $\frac{1}{2}r^2\theta$ seen or used |
| $6\times 3 = 2\times\frac{1}{2}\times 6^2\times\theta$ | m1 | OE Forming equation |
| $36\theta = 18 \Rightarrow \theta = 0.5$ | A1 | AG — **Total: 3** |

### Part (b)
| Working | Mark | Guidance |
|---------|------|----------|
| Arc $= 6\theta$ | M1 | $r\theta$ seen or used |
| $\ldots = 3$ cm | A1 | PI by a correct perimeter |
| $\Rightarrow$ Perimeter $= 12 +$ arc $= 15$ cm | A1F | Ft wrong evaluation of $6\theta$. Condone missing/wrong units — **Total: 3** |

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1 The diagrams show a rectangle of length 6 cm and width 3 cm , and a sector of a circle of radius 6 cm and angle $\theta$ radians.\\
\includegraphics[max width=\textwidth, alt={}, center]{14c2acbb-5f3e-40e2-8b88-162341ab9f71-2_266_1128_589_424}

The area of the rectangle is twice the area of the sector.
\begin{enumerate}[label=(\alph*)]
\item Show that $\theta = 0.5$.
\item Find the perimeter of the sector.
\end{enumerate}

\hfill \mbox{\textit{AQA C2 2008 Q1 [6]}}