AQA C2 2005 January — Question 5

Exam BoardAQA
ModuleC2 (Core Mathematics 2)
Year2005
SessionJanuary
TopicLaws of Logarithms

5
  1. Given that $$\log _ { a } x = 3 \log _ { a } 6 - \log _ { a } 8$$ where \(a\) is a positive constant, show that \(x = 27\).
  2. Write down the value of:
    1. \(\quad \log _ { 4 } 1\);
    2. \(\log _ { 4 } 4\);
    3. \(\log _ { 4 } 2\);
    4. \(\quad \log _ { 4 } 8\).