CAIE P2 2008 November — Question 4 6 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2008
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeShow equation reduces to tan form
DifficultyModerate -0.3 This is a straightforward application of addition formulae followed by routine algebraic manipulation and solving a basic tan equation. Part (i) requires expanding sin(x+30°) and cos(x+60°) using standard formulae, then simplifying—mechanical but with several steps. Part (ii) is immediate once part (i) is done: rearrange to tan x = 1/(3√3) and find solutions in the given range. The question is slightly below average difficulty because it's a standard textbook exercise with clear structure and no novel insight required, though the algebraic manipulation requires care.
Spec1.05a Sine, cosine, tangent: definitions for all arguments1.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals

4
  1. Show that the equation $$\sin \left( x + 30 ^ { \circ } \right) = 2 \cos \left( x + 60 ^ { \circ } \right)$$ can be written in the form $$( 3 \sqrt { } 3 ) \sin x = \cos x$$
  2. Hence solve the equation $$\sin \left( x + 30 ^ { \circ } \right) = 2 \cos \left( x + 60 ^ { \circ } \right)$$ for \(- 180 ^ { \circ } \leqslant x \leqslant 180 ^ { \circ }\).

AnswerMarks Guidance
(i) Use correct \(\sin(A + B)\) and \(\cos(A + B)\) formulaeM1
Substitute exact values for sin 30° etc.M1
Obtain given answer correctlyA1 [3]
(ii) Solve for \(x\)M1
Obtain answer \(x = 10.9°\)A1
Obtain second answer \(x = -169.1°\) and no others in the rangeA1 [3]
[Ignore answers outside the given range.]
**(i)** Use correct $\sin(A + B)$ and $\cos(A + B)$ formulae | M1 |
Substitute exact values for sin 30° etc. | M1 |
Obtain given answer correctly | A1 | [3]

**(ii)** Solve for $x$ | M1 |
Obtain answer $x = 10.9°$ | A1 |
Obtain second answer $x = -169.1°$ and no others in the range | A1 | [3]
[Ignore answers outside the given range.]
4 (i) Show that the equation

$$\sin \left( x + 30 ^ { \circ } \right) = 2 \cos \left( x + 60 ^ { \circ } \right)$$

can be written in the form

$$( 3 \sqrt { } 3 ) \sin x = \cos x$$

(ii) Hence solve the equation

$$\sin \left( x + 30 ^ { \circ } \right) = 2 \cos \left( x + 60 ^ { \circ } \right)$$

for $- 180 ^ { \circ } \leqslant x \leqslant 180 ^ { \circ }$.

\hfill \mbox{\textit{CAIE P2 2008 Q4 [6]}}