Edexcel C1 — Question 7 10 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Functions
TypeSolve exponential equation by substitution
DifficultyModerate -0.8 This is a structured, multi-part C1 question that guides students through each step of solving an exponential equation via substitution. Part (a) tests basic index law manipulation, part (b) is a 'show that' requiring straightforward algebraic substitution, and part (c) involves solving a quadratic then taking logarithms. The scaffolding makes this easier than average, requiring only routine application of standard techniques with no problem-solving insight needed.
Spec1.02f Solve quadratic equations: including in a function of unknown1.06g Equations with exponentials: solve a^x = b

7. (a) Given that \(y = 2 ^ { x }\), find expressions in terms of \(y\) for
  1. \(2 ^ { x + 2 }\),
  2. \(2 ^ { 3 - x }\).
    (b) Show that using the substitution \(y = 2 ^ { x }\), the equation $$2 ^ { x + 2 } + 2 ^ { 3 - x } = 33$$ can be rewritten as $$4 y ^ { 2 } - 33 y + 8 = 0$$ (c) Hence solve the equation $$2 ^ { x + 2 } + 2 ^ { 3 - x } = 33$$

AnswerMarks Guidance
(a) (i) \(2^{x+2} = 2^x \times 2^1 = 4y\)M1 A1
(ii) \(2^{1-x} = \frac{2^1}{2^x} = \frac{8}{y}\)M1 A1
(b) \(2^{x+2} + 2^{3-x} = 33 \Rightarrow 4y + \frac{8}{y} = 33\)
\(4y^2 + 8 = 33y\)M1
\(4y^2 - 33y + 8 = 0\)A1
(c) \((4y - 1)(y - 8) = 0\)M1
\(y = \frac{1}{4}, 8\)A1
\(2^x = \frac{1}{4}, 8\)
\(x = -2, 3\)A2 (10 marks)
**(a)** (i) $2^{x+2} = 2^x \times 2^1 = 4y$ | M1 A1 |

(ii) $2^{1-x} = \frac{2^1}{2^x} = \frac{8}{y}$ | M1 A1 |

**(b)** $2^{x+2} + 2^{3-x} = 33 \Rightarrow 4y + \frac{8}{y} = 33$ | |
$4y^2 + 8 = 33y$ | M1 |
$4y^2 - 33y + 8 = 0$ | A1 |

**(c)** $(4y - 1)(y - 8) = 0$ | M1 |
$y = \frac{1}{4}, 8$ | A1 |
$2^x = \frac{1}{4}, 8$ | |
$x = -2, 3$ | A2 | (10 marks)
7. (a) Given that $y = 2 ^ { x }$, find expressions in terms of $y$ for
\begin{enumerate}[label=(\roman*)]
\item $2 ^ { x + 2 }$,
\item $2 ^ { 3 - x }$.\\
(b) Show that using the substitution $y = 2 ^ { x }$, the equation

$$2 ^ { x + 2 } + 2 ^ { 3 - x } = 33$$

can be rewritten as

$$4 y ^ { 2 } - 33 y + 8 = 0$$

(c) Hence solve the equation

$$2 ^ { x + 2 } + 2 ^ { 3 - x } = 33$$
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1  Q7 [10]}}