Edexcel C1 — Question 4 6 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard Integrals and Reverse Chain Rule
TypeFind curve equation from derivative (straightforward integration + point)
DifficultyEasy -1.3 This is a straightforward integration question requiring only the power rule and finding a constant using initial conditions. It's a standard C1 exercise with minimal steps: integrate, apply boundary condition, substitute x=2. No problem-solving or conceptual insight needed beyond basic technique.
Spec1.08b Integrate x^n: where n != -1 and sums1.08d Evaluate definite integrals: between limits

4. Given that $$\frac { \mathrm { d } y } { \mathrm {~d} x } = 2 x ^ { 3 } + 1 ,$$ and that \(y = 3\) when \(x = 0\), find the value of \(y\) when \(x = 2\).

AnswerMarks Guidance
\(y = \int (2x^3 + 1) \, dx\)M1 A2
\(y = \frac{1}{2}x^4 + x + c\)
\(x = 0, y = 3\) ⇒ \(c = 3\)B1
\(y = \frac{1}{2}x^4 + x + 3\)M1 A1
when \(x = 2\), \(y = 8 + 2 + 3 = 13\)M1 A1 (6 marks)
$y = \int (2x^3 + 1) \, dx$ | M1 A2 |
$y = \frac{1}{2}x^4 + x + c$ | |
$x = 0, y = 3$ ⇒ $c = 3$ | B1 |
$y = \frac{1}{2}x^4 + x + 3$ | M1 A1 |
when $x = 2$, $y = 8 + 2 + 3 = 13$ | M1 A1 | (6 marks)
4. Given that

$$\frac { \mathrm { d } y } { \mathrm {~d} x } = 2 x ^ { 3 } + 1 ,$$

and that $y = 3$ when $x = 0$, find the value of $y$ when $x = 2$.\\

\hfill \mbox{\textit{Edexcel C1  Q4 [6]}}