Edexcel S3 2021 October — Question 1 5 marks

Exam BoardEdexcel
ModuleS3 (Statistics 3)
Year2021
SessionOctober
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicZ-tests (known variance)
TypeOne-tail z-test (lower tail)
DifficultyModerate -0.3 This is a straightforward one-sample z-test with all information provided directly: known variance, clear hypotheses, and standard 5% significance level. Students must set up H₀: μ=30 vs H₁: μ<30, calculate z = (29.5-30)/(2.5/√80) ≈ -1.79, and compare to critical value -1.645. While it requires proper hypothesis test structure, it's a textbook application with no conceptual challenges or multi-step reasoning, making it slightly easier than average.
Spec2.04e Normal distribution: as model N(mu, sigma^2)2.04f Find normal probabilities: Z transformation2.05e Hypothesis test for normal mean: known variance

  1. A machine makes screws with a mean length of 30 mm and a standard deviation of 2.5 mm .
A manager claims that, following some repairs, the machine is now making screws with a mean length of less than 30 mm . The manager takes a random sample of 80 screws and finds that they have a mean length of 29.5 mm . Use a suitable test, at the \(5 \%\) level of significance, to determine whether there is evidence to support the manager's claim. State your hypotheses clearly.

Question 1:
AnswerMarks Guidance
Answer/WorkingMark Guidance Notes
\(H_0: \mu = 30 \quad H_1: \mu < 30\)B1 Both hypotheses correct in terms of \(\mu\)
\(z = \dfrac{29.5 - 30}{\dfrac{2.5}{\sqrt{80}}}\)M1 For attempting test statistic, allow \(\pm\). Condone \(\sqrt{\dfrac{2.5}{80}}\)
\(z = -1.7888\ldots\) awrt \(-1.79\)A1 Allow \(\
\(-1.7888 < -1.6449\)B1 \(\
Reject \(H_0\) or significant result or in the critical region. There is evidence to support the manager's claim.A1 For correct conclusion. Allow the manager's claim in words if it includes screws and less (oe)
Total5
## Question 1:

| Answer/Working | Mark | Guidance Notes |
|---|---|---|
| $H_0: \mu = 30 \quad H_1: \mu < 30$ | B1 | Both hypotheses correct in terms of $\mu$ |
| $z = \dfrac{29.5 - 30}{\dfrac{2.5}{\sqrt{80}}}$ | M1 | For attempting test statistic, allow $\pm$. Condone $\sqrt{\dfrac{2.5}{80}}$ |
| $z = -1.7888\ldots$ awrt $-1.79$ | A1 | Allow $\|z\| = 1.7888\ldots$ Allow $p$ value of $0.0367$ or awrt $0.0368$ or $CR \leqslant 29.54$ |
| $-1.7888 < -1.6449$ | B1 | $\|CV\| = 1.6449$ or better (ignore any comparisons). Allow $CR \leqslant 29.54$. SC: If $p$ value of $0.0367$ or awrt $0.0368$, award B1 if 2nd A1 is awarded |
| Reject $H_0$ or significant result or in the critical region. There is evidence to support the manager's claim. | A1 | For correct conclusion. Allow the manager's claim in words if it includes screws and less (oe) |
| **Total** | **5** | |
\begin{enumerate}
  \item A machine makes screws with a mean length of 30 mm and a standard deviation of 2.5 mm .
\end{enumerate}

A manager claims that, following some repairs, the machine is now making screws with a mean length of less than 30 mm . The manager takes a random sample of 80 screws and finds that they have a mean length of 29.5 mm .

Use a suitable test, at the $5 \%$ level of significance, to determine whether there is evidence to support the manager's claim. State your hypotheses clearly.

\hfill \mbox{\textit{Edexcel S3 2021 Q1 [5]}}