| Exam Board | Edexcel |
|---|---|
| Module | S2 (Statistics 2) |
| Year | 2013 |
| Session | June |
| Marks | 9 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Continuous Uniform Random Variables |
| Type | Derive or verify variance formula |
| Difficulty | Moderate -0.3 This is a straightforward S2 question testing standard uniform distribution properties. Part (a) requires recalling E(X) = (a+b)/2, part (b) is a guided integration using Var(X) = E(X²) - [E(X)]² with explicit instruction to 'show that', parts (c-e) apply standard formulas for variance of linear transformations, CDF definition, and median. All steps are routine applications of bookwork with no problem-solving or novel insight required, making it slightly easier than average. |
| Spec | 5.02e Discrete uniform distribution5.03e Find cdf: by integration5.03f Relate pdf-cdf: medians and percentiles5.04a Linear combinations: E(aX+bY), Var(aX+bY) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| \(E(X) = \frac{5b}{2}\) | B1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| \(\text{Var}(X) = E(X^2) - (E(X))^2\) | M1 | Using \(\int \frac{x^2}{3b}\,dx - (\text{their }(a))^2\); limits not needed |
| \(= \int_b^{4b} \frac{x^2}{3b}\,dx - \left(\frac{5b}{2}\right)^2\) | M1d | Dependent on previous M; correct integration \(x^n \to x^{n+1}\) and correct limits |
| \(= \left[\frac{x^3}{9b}\right]_b^{4b} - \frac{25b^2}{4}\) | ||
| \(= \frac{63b^3}{9b} - \frac{25b^2}{4}\) | ||
| \(= \frac{3b^2}{4}\) | A1cso | Correct solution with no incorrect working; answer given so must show working |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| \(\text{Var}(3 - 2X) = 4\text{Var}(X)\) | M1 | Writing or using \(4\text{Var}(X)\) |
| \(= 3b^2\) | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| \(F(x) = \begin{cases} 0 & x < 1 \\ \frac{x-1}{3} & 1 \leq x \leq 4 \\ 1 & x > 4 \end{cases}\) | B1B1 | 1st B1: top and bottom line (allow \(\leq\) instead of \(<\) and \(\geq\) instead of \(>\)); 2nd B1: middle row (allow \(<\) instead of \(\leq\)) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| \(\frac{x-1}{3} = 0.5\) so \(x = 2.5\) | B1 |
# Question 4:
## Part 4(a):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $E(X) = \frac{5b}{2}$ | B1 | |
## Part 4(b):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\text{Var}(X) = E(X^2) - (E(X))^2$ | M1 | Using $\int \frac{x^2}{3b}\,dx - (\text{their }(a))^2$; limits not needed |
| $= \int_b^{4b} \frac{x^2}{3b}\,dx - \left(\frac{5b}{2}\right)^2$ | M1d | Dependent on previous M; correct integration $x^n \to x^{n+1}$ and correct limits |
| $= \left[\frac{x^3}{9b}\right]_b^{4b} - \frac{25b^2}{4}$ | | |
| $= \frac{63b^3}{9b} - \frac{25b^2}{4}$ | | |
| $= \frac{3b^2}{4}$ | A1cso | Correct solution with no incorrect working; answer given so must show working |
## Part 4(c):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\text{Var}(3 - 2X) = 4\text{Var}(X)$ | M1 | Writing or using $4\text{Var}(X)$ |
| $= 3b^2$ | A1 | |
## Part 4(d):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $F(x) = \begin{cases} 0 & x < 1 \\ \frac{x-1}{3} & 1 \leq x \leq 4 \\ 1 & x > 4 \end{cases}$ | B1B1 | 1st B1: top and bottom line (allow $\leq$ instead of $<$ and $\geq$ instead of $>$); 2nd B1: middle row (allow $<$ instead of $\leq$) |
## Part 4(e):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\frac{x-1}{3} = 0.5$ so $x = 2.5$ | B1 | |
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\begin{enumerate}
\item A continuous random variable $X$ is uniformly distributed over the interval [ $b , 4 b$ ] where $b$ is a constant.\\
(a) Write down $\mathrm { E } ( X )$.\\
(b) Use integration to show that $\operatorname { Var } ( X ) = \frac { 3 b ^ { 2 } } { 4 }$.\\
(c) Find $\operatorname { Var } ( 3 - 2 X )$.
\end{enumerate}
Given that $b = 1$ find\\
(d) the cumulative distribution function of $X , \mathrm {~F} ( x )$, for all values of $x$,\\
(e) the median of $X$.\\
\hfill \mbox{\textit{Edexcel S2 2013 Q4 [9]}}