OCR Further Pure Core 2 2022 June — Question 4 4 marks

Exam BoardOCR
ModuleFurther Pure Core 2 (Further Pure Core 2)
Year2022
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSequences and series, recurrence and convergence
TypeLimit of ratio of sums
DifficultyStandard +0.8 This requires knowing or deriving formulas for sum of squares (n(n+1)(2n+1)/6) and sum of integers (n(n+1)/2), simplifying the ratio to (2n+1)/3, then solving an inequality. It's a multi-step problem requiring formula recall and algebraic manipulation, moderately harder than average but standard for Further Maths.
Spec4.01a Mathematical induction: construct proofs4.06a Summation formulae: sum of r, r^2, r^3

4 In this question you must show detailed reasoning.
Determine the smallest value of \(n\) for which \(\frac { 1 ^ { 2 } + 2 ^ { 2 } + \ldots + n ^ { 2 } } { 1 + 2 + \ldots + n } > 341\).

4 In this question you must show detailed reasoning.\\
Determine the smallest value of $n$ for which $\frac { 1 ^ { 2 } + 2 ^ { 2 } + \ldots + n ^ { 2 } } { 1 + 2 + \ldots + n } > 341$.

\hfill \mbox{\textit{OCR Further Pure Core 2 2022 Q4 [4]}}