OCR Further Pure Core 1 2020 November — Question 1 2 marks

Exam BoardOCR
ModuleFurther Pure Core 1 (Further Pure Core 1)
Year2020
SessionNovember
Marks2
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndefinite & Definite Integrals
TypeMean value of function
DifficultyEasy -1.2 This is a straightforward application of the mean value formula requiring only integration of a simple polynomial and division by the interval length. While it's a Further Maths question, the technique is routine with no problem-solving or conceptual challenge beyond recalling the formula.
Spec4.08e Mean value of function: using integral
1 Find the mean value of \(\mathrm { f } ( x ) = x ^ { 2 } + 6 x\) over the interval \([ 0,3 ]\).
Question 1:
AnswerMarks
11 3
Mean value = ∫f(x)dx
3
0
1 3
= ∫x2 +6xdx=12
3
AnswerMarks
0M1
A11.1
1.1Use the correct formula
BC
[2]
Question 1:
1 | 1 3
Mean value = ∫f(x)dx
3
0
1 3
= ∫x2 +6xdx=12
3
0 | M1
A1 | 1.1
1.1 | Use the correct formula
BC
[2]
1 Find the mean value of $\mathrm { f } ( x ) = x ^ { 2 } + 6 x$ over the interval $[ 0,3 ]$.

\hfill \mbox{\textit{OCR Further Pure Core 1 2020 Q1 [2]}}
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Q1 2 Q2 3 Q3 5 Q4 4 Q5 5 Q6 5 Q7 5 Q8 10 Q9 9 Q10 13 Q11 8 Q12 6