OCR Further Pure Core 1 2024 June — Question 6 4 marks

Exam BoardOCR
ModuleFurther Pure Core 1 (Further Pure Core 1)
Year2024
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIntegration using inverse trig and hyperbolic functions
TypeImproper integral to infinity with inverse trig
DifficultyChallenging +1.2 This improper integral requires recognizing the substitution u = √x (or direct integration using power rules), evaluating limits at infinity, and handling the improper nature carefully. While it involves multiple steps and requires proper treatment of the infinite limit, the algebraic manipulation is straightforward once the substitution is made, and the convergence is clear. It's moderately harder than average due to the improper integral aspect and need for detailed reasoning, but doesn't require particularly deep insight or novel techniques.
Spec4.08c Improper integrals: infinite limits or discontinuous integrands

6 In this question you must show detailed reasoning.
Determine the exact value of \(\int _ { 9 } ^ { \infty } \frac { 18 } { x ^ { 2 } \sqrt { x } } \mathrm {~d} x\).

Question 6:
AnswerMarks
6DR
 18  2 − 3
dx=18− x 2(+c)
 x2 x  3 
 2 − 3  2 − 3 
=18lim− k 2 −− 9 2 
 
k→ 3  3 
32
k → 0 as k → 
4
=
AnswerMarks
9M1*
M1
B1dep*
A1
AnswerMarks
[4]1.1
1.1
2.1
AnswerMarks
2.2a32
For obtaining a x where a0.
Correct use of 9 as a lower limit and any letter (except x) for the upper
limit (so must be considering a finite upper limit) in their integrated
expression (indicated by their power increased by 1). Need not see
mention of limiting process for this mark.
32
Taking limit as 𝑘 → ∞ for their expression of the form a x (so
1
=0oe is B0). Implied by, for example,
3
 2 − 32 
lk i m→ − k − ... = 0 − ... but not, for example, for
 3
2 − 3
− k 2 −...=0−... without clear use of limiting process.
3
cao from correct integrated expression and finite upper limit (so
dependent on both previous M marks but not the B mark). Accept
equivalent exact forms e.g. 12.
27
Question 6:
6 | DR
 18  2 − 3
dx=18− x 2(+c)

 x2 x  3 
 2 − 3  2 − 3 
=18lim− k 2 −− 9 2 
 
k→ 3  3 
32
−
k → 0 as k → 
4
=
9 | M1*
M1
B1dep*
A1
[4] | 1.1
1.1
2.1
2.2a | 32
−
For obtaining a x where a0.
Correct use of 9 as a lower limit and any letter (except x) for the upper
limit (so must be considering a finite upper limit) in their integrated
expression (indicated by their power increased by 1). Need not see
mention of limiting process for this mark.
32
−
Taking limit as 𝑘 → ∞ for their expression of the form a x (so
1
=0oe is B0). Implied by, for example,
3
 2 − 32 
lk i m→ − k − ... = 0 − ... but not, for example, for
 3
2 − 3
− k 2 −...=0−... without clear use of limiting process.
3
cao from correct integrated expression and finite upper limit (so
dependent on both previous M marks but not the B mark). Accept
equivalent exact forms e.g. 12.
27
6 In this question you must show detailed reasoning.\\
Determine the exact value of $\int _ { 9 } ^ { \infty } \frac { 18 } { x ^ { 2 } \sqrt { x } } \mathrm {~d} x$.

\hfill \mbox{\textit{OCR Further Pure Core 1 2024 Q6 [4]}}