OCR Further Mechanics AS 2021 November — Question 1 7 marks

Exam BoardOCR
ModuleFurther Mechanics AS (Further Mechanics AS)
Year2021
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircular Motion 1
TypeConical pendulum – particle on horizontal surface
DifficultyEasy -1.2 This is a straightforward application of basic circular motion formulas (ω = 2π/T, v = rω, a = v²/r) with direct substitution of given values. All parts are standard recall with minimal problem-solving, making it easier than average A-level questions which typically require more synthesis or multi-step reasoning.
Spec6.05a Angular velocity: definitions6.05b Circular motion: v=r*omega and a=v^2/r

1 One end of a light inextensible string of length 2.8 m is attached to a fixed point \(O\) on a smooth horizontal table. The other end of the string is attached to a particle \(P\) which moves on the table, with the string taut, in a circular path around \(O\). The speed of \(P\) is constant and \(P\) completes each circle in 0.84 seconds.
  1. Find the magnitude of the angular velocity of \(P\).
  2. Find the speed of \(P\).
  3. Find the magnitude of the acceleration of \(P\).
  4. State the direction of the acceleration of \(P\).

Question 1:
Part (a)
AnswerMarks Guidance
\(\omega = 2\pi / 0.84\) soiM1 Correct formula for angular velocity used
awrt \(7.48\) rad s\(^{-1}\)A1 \(\left(\frac{50}{21}\pi\right)\)
Part (b)
AnswerMarks Guidance
\(v = 2.8 \times\) "7.48..." or \(2\pi \times 2.8 / 0.84\)M1 Correct formula for speed used \(\left(\frac{20}{3}\pi\right)\); FT their value for \(\omega\) if used
awrt \(20.9\) m s\(^{-1}\)A1
Part (c)
AnswerMarks Guidance
\(a =\) "20.9..."\(^2 / 2.8\) or \(2.8 \times\) "7.48..."\(^2\) or "20.9..." \(\times\) "7.48..."M1 Any correct formula for acceleration used; FT their value for \(v\) if used
awrt \(157\) (or \(156\)) ms\(^{-2}\)A1 \(156\) if rounded values used \(\left(\frac{1000}{63}\pi^2\right)\)
Part (d)
AnswerMarks Guidance
...towards \(O\)B1 Any indication that the acceleration is towards the centre of the circle
# Question 1:

## Part (a)
$\omega = 2\pi / 0.84$ soi | **M1** | Correct formula for angular velocity used
awrt $7.48$ rad s$^{-1}$ | **A1** | $\left(\frac{50}{21}\pi\right)$

## Part (b)
$v = 2.8 \times$ "7.48..." or $2\pi \times 2.8 / 0.84$ | **M1** | Correct formula for speed used $\left(\frac{20}{3}\pi\right)$; FT their value for $\omega$ if used
awrt $20.9$ m s$^{-1}$ | **A1** |

## Part (c)
$a =$ "20.9..."$^2 / 2.8$ or $2.8 \times$ "7.48..."$^2$ or "20.9..." $\times$ "7.48..." | **M1** | Any correct formula for acceleration used; FT their value for $v$ if used
awrt $157$ (or $156$) ms$^{-2}$ | **A1** | $156$ if rounded values used $\left(\frac{1000}{63}\pi^2\right)$

## Part (d)
...towards $O$ | **B1** | Any indication that the acceleration is towards the centre of the circle

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1 One end of a light inextensible string of length 2.8 m is attached to a fixed point $O$ on a smooth horizontal table. The other end of the string is attached to a particle $P$ which moves on the table, with the string taut, in a circular path around $O$. The speed of $P$ is constant and $P$ completes each circle in 0.84 seconds.
\begin{enumerate}[label=(\alph*)]
\item Find the magnitude of the angular velocity of $P$.
\item Find the speed of $P$.
\item Find the magnitude of the acceleration of $P$.
\item State the direction of the acceleration of $P$.
\end{enumerate}

\hfill \mbox{\textit{OCR Further Mechanics AS 2021 Q1 [7]}}