Easy -1.2 This is a straightforward recall question testing knowledge that the sum of independent Poisson distributions is Poisson with mean equal to the sum of means. The only minor complication is recognizing that standard deviation 4 means mean 16 (since variance equals mean for Poisson), but this is basic Poisson theory. It's a 1-mark multiple choice question requiring no calculation or problem-solving.
2 The random variable \(A\) has a Poisson distribution with mean 2
The random variable \(B\) has a Poisson distribution with standard deviation 4
The random variables \(A\) and \(B\) are independent.
State the distribution of \(A + B\)
Circle your answer. [0pt]
[1 mark]
Po(4)
Po(6)
Po(8)
Po(18)
2 The random variable $A$ has a Poisson distribution with mean 2
The random variable $B$ has a Poisson distribution with standard deviation 4
The random variables $A$ and $B$ are independent.\\
State the distribution of $A + B$
Circle your answer.\\[0pt]
[1 mark]\\
Po(4)\\
Po(6)\\
Po(8)\\
Po(18)
\hfill \mbox{\textit{AQA Further AS Paper 2 Statistics 2021 Q2 [1]}}