OCR MEI Paper 3 2020 November — Question 5 11 marks

Exam BoardOCR MEI
ModulePaper 3 (Paper 3)
Year2020
SessionNovember
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicReciprocal Trig & Identities
TypeSketch reciprocal function graphs
DifficultyStandard +0.3 This is a structured multi-part question on cosec x covering standard A-level content: identifying asymptotes and turning points from a graph, showing a root exists using sign change, performing straightforward iteration calculations, and sketching a cobweb diagram. While part (d) requires understanding of convergence and part (e) requires a cobweb sketch, these are routine applications of taught techniques with no novel problem-solving required. Slightly easier than average due to the scaffolded structure and standard nature of all parts.
Spec1.05h Reciprocal trig functions: sec, cosec, cot definitions and graphs1.09a Sign change methods: locate roots1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams1.09d Newton-Raphson method

5 Fig. 5 shows part of the curve \(y = \operatorname { cosec } x\) together with the \(x\) - and \(y\)-axes. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{a13f7a05-e2d3-4354-a0c7-ef7283eff514-06_732_625_317_244} \captionsetup{labelformat=empty} \caption{Fig. 5}
\end{figure}
  1. For the section of the curve which is shown in Fig. 5, write down
    1. the equations of the two vertical asymptotes,
    2. the coordinates of the minimum point.
  2. Show that the equation \(x = \operatorname { cosec } x\) has a root which lies between \(x = 1\) and \(x = 2\).
  3. Use the iteration \(\mathrm { x } _ { \mathrm { n } + 1 } = \operatorname { cosec } \left( \mathrm { x } _ { \mathrm { n } } \right)\), with \(x _ { 0 } = 1\), to find
    1. the values of \(x _ { 1 }\) and \(x _ { 2 }\), correct to 5 decimal places,
    2. this root of the equation, correct to 3 decimal places.
  4. There is another root of \(x = \operatorname { cosec } x\) which lies between \(x = 2\) and \(x = 3\). Determine whether the iteration \(\mathrm { x } _ { \mathrm { n } + 1 } = \operatorname { cosec } \left( \mathrm { x } _ { \mathrm { n } } \right)\) with \(x _ { 0 } = 2.5\) converges to this root.
  5. Sketch the staircase or cobweb diagram for the iteration, starting with \(x _ { 0 } = 2.5\), on the diagram in the Printed Answer Booklet.

Question 5(a)(i):
AnswerMarks Guidance
AnswerMarks Guidance
\(x=0\)B1 If answers given in both degrees and radians follow inst 2g
\(x=\pi\)B1 180 gets 0
Question 5(a)(ii):
AnswerMarks Guidance
AnswerMarks Guidance
\(\left(\frac{\pi}{2},\ 1\right)\)B1 \((90, 1)\) or \((1.57, 1)\) get 0
Question 5(b):
AnswerMarks Guidance
AnswerMarks Guidance
\(1 - \cosec1 = -0.188...\) or 'negative'; \(2 - \cosec2 = 0.900...\) or 'positive'B1 Both correct. OE e.g. may use \(\cosec x - x\)
Change of sign so root between 1 and 2E1 Condone no mention of continuity AG. Dep on B mark
Question 5(c)(i):
AnswerMarks Guidance
AnswerMarks Guidance
BC: \(1.18840...,\ 1.07785...\)B1 Both correct to at least 3 d.p.
Question 5(c)(ii):
AnswerMarks Guidance
AnswerMarks Guidance
BC: \(1.114\)B1
Question 5(d):
AnswerMarks Guidance
AnswerMarks Guidance
No, it converges to \(1.114\)E1 OR same as *their* (c)(ii) or 'the root between 1 and 2' etc. Just 'No' gets 0; 'Yes' with anything gets 0
Question 5(e):
AnswerMarks Guidance
AnswerMarks Guidance
[Cobweb/staircase diagram] Starting point between min and right asymptoteB1 3 B marks all independent
Initial "staircase" (\(\geq 2\) horizontal sections)B1
Spirals into lower rootB1
## Question 5(a)(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $x=0$ | B1 | If answers given in both degrees and radians follow inst 2g |
| $x=\pi$ | B1 | 180 gets 0 |

---

## Question 5(a)(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\left(\frac{\pi}{2},\ 1\right)$ | B1 | $(90, 1)$ or $(1.57, 1)$ get 0 |

---

## Question 5(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $1 - \cosec1 = -0.188...$ or 'negative'; $2 - \cosec2 = 0.900...$ or 'positive' | B1 | Both correct. OE e.g. may use $\cosec x - x$ |
| Change of sign so root between 1 and 2 | E1 | Condone no mention of continuity AG. Dep on B mark |

---

## Question 5(c)(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| BC: $1.18840...,\ 1.07785...$ | B1 | Both correct to at least 3 d.p. |

---

## Question 5(c)(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| BC: $1.114$ | B1 | |

---

## Question 5(d):

| Answer | Marks | Guidance |
|--------|-------|----------|
| No, it converges to $1.114$ | E1 | OR same as *their* (c)(ii) or 'the root between 1 and 2' etc. Just 'No' gets 0; 'Yes' with anything gets 0 |

---

## Question 5(e):

| Answer | Marks | Guidance |
|--------|-------|----------|
| [Cobweb/staircase diagram] Starting point between min and right asymptote | B1 | 3 B marks all independent |
| Initial "staircase" ($\geq 2$ horizontal sections) | B1 | |
| Spirals into lower root | B1 | |

---
5 Fig. 5 shows part of the curve $y = \operatorname { cosec } x$ together with the $x$ - and $y$-axes.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{a13f7a05-e2d3-4354-a0c7-ef7283eff514-06_732_625_317_244}
\captionsetup{labelformat=empty}
\caption{Fig. 5}
\end{center}
\end{figure}
\begin{enumerate}[label=(\alph*)]
\item For the section of the curve which is shown in Fig. 5, write down
\begin{enumerate}[label=(\roman*)]
\item the equations of the two vertical asymptotes,
\item the coordinates of the minimum point.
\end{enumerate}\item Show that the equation $x = \operatorname { cosec } x$ has a root which lies between $x = 1$ and $x = 2$.
\item Use the iteration $\mathrm { x } _ { \mathrm { n } + 1 } = \operatorname { cosec } \left( \mathrm { x } _ { \mathrm { n } } \right)$, with $x _ { 0 } = 1$, to find
\begin{enumerate}[label=(\roman*)]
\item the values of $x _ { 1 }$ and $x _ { 2 }$, correct to 5 decimal places,
\item this root of the equation, correct to 3 decimal places.
\end{enumerate}\item There is another root of $x = \operatorname { cosec } x$ which lies between $x = 2$ and $x = 3$.

Determine whether the iteration $\mathrm { x } _ { \mathrm { n } + 1 } = \operatorname { cosec } \left( \mathrm { x } _ { \mathrm { n } } \right)$ with $x _ { 0 } = 2.5$ converges to this root.
\item Sketch the staircase or cobweb diagram for the iteration, starting with $x _ { 0 } = 2.5$, on the diagram in the Printed Answer Booklet.
\end{enumerate}

\hfill \mbox{\textit{OCR MEI Paper 3 2020 Q5 [11]}}