| Exam Board | OCR MEI |
|---|---|
| Module | Paper 3 (Paper 3) |
| Year | 2020 |
| Session | November |
| Marks | 11 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Reciprocal Trig & Identities |
| Type | Sketch reciprocal function graphs |
| Difficulty | Standard +0.3 This is a structured multi-part question on cosec x covering standard A-level content: identifying asymptotes and turning points from a graph, showing a root exists using sign change, performing straightforward iteration calculations, and sketching a cobweb diagram. While part (d) requires understanding of convergence and part (e) requires a cobweb sketch, these are routine applications of taught techniques with no novel problem-solving required. Slightly easier than average due to the scaffolded structure and standard nature of all parts. |
| Spec | 1.05h Reciprocal trig functions: sec, cosec, cot definitions and graphs1.09a Sign change methods: locate roots1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams1.09d Newton-Raphson method |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| \(x=0\) | B1 | If answers given in both degrees and radians follow inst 2g |
| \(x=\pi\) | B1 | 180 gets 0 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| \(\left(\frac{\pi}{2},\ 1\right)\) | B1 | \((90, 1)\) or \((1.57, 1)\) get 0 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| \(1 - \cosec1 = -0.188...\) or 'negative'; \(2 - \cosec2 = 0.900...\) or 'positive' | B1 | Both correct. OE e.g. may use \(\cosec x - x\) |
| Change of sign so root between 1 and 2 | E1 | Condone no mention of continuity AG. Dep on B mark |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| BC: \(1.18840...,\ 1.07785...\) | B1 | Both correct to at least 3 d.p. |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| BC: \(1.114\) | B1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| No, it converges to \(1.114\) | E1 | OR same as *their* (c)(ii) or 'the root between 1 and 2' etc. Just 'No' gets 0; 'Yes' with anything gets 0 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| [Cobweb/staircase diagram] Starting point between min and right asymptote | B1 | 3 B marks all independent |
| Initial "staircase" (\(\geq 2\) horizontal sections) | B1 | |
| Spirals into lower root | B1 |
## Question 5(a)(i):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $x=0$ | B1 | If answers given in both degrees and radians follow inst 2g |
| $x=\pi$ | B1 | 180 gets 0 |
---
## Question 5(a)(ii):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $\left(\frac{\pi}{2},\ 1\right)$ | B1 | $(90, 1)$ or $(1.57, 1)$ get 0 |
---
## Question 5(b):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $1 - \cosec1 = -0.188...$ or 'negative'; $2 - \cosec2 = 0.900...$ or 'positive' | B1 | Both correct. OE e.g. may use $\cosec x - x$ |
| Change of sign so root between 1 and 2 | E1 | Condone no mention of continuity AG. Dep on B mark |
---
## Question 5(c)(i):
| Answer | Marks | Guidance |
|--------|-------|----------|
| BC: $1.18840...,\ 1.07785...$ | B1 | Both correct to at least 3 d.p. |
---
## Question 5(c)(ii):
| Answer | Marks | Guidance |
|--------|-------|----------|
| BC: $1.114$ | B1 | |
---
## Question 5(d):
| Answer | Marks | Guidance |
|--------|-------|----------|
| No, it converges to $1.114$ | E1 | OR same as *their* (c)(ii) or 'the root between 1 and 2' etc. Just 'No' gets 0; 'Yes' with anything gets 0 |
---
## Question 5(e):
| Answer | Marks | Guidance |
|--------|-------|----------|
| [Cobweb/staircase diagram] Starting point between min and right asymptote | B1 | 3 B marks all independent |
| Initial "staircase" ($\geq 2$ horizontal sections) | B1 | |
| Spirals into lower root | B1 | |
---
5 Fig. 5 shows part of the curve $y = \operatorname { cosec } x$ together with the $x$ - and $y$-axes.
\begin{figure}[h]
\begin{center}
\includegraphics[alt={},max width=\textwidth]{a13f7a05-e2d3-4354-a0c7-ef7283eff514-06_732_625_317_244}
\captionsetup{labelformat=empty}
\caption{Fig. 5}
\end{center}
\end{figure}
\begin{enumerate}[label=(\alph*)]
\item For the section of the curve which is shown in Fig. 5, write down
\begin{enumerate}[label=(\roman*)]
\item the equations of the two vertical asymptotes,
\item the coordinates of the minimum point.
\end{enumerate}\item Show that the equation $x = \operatorname { cosec } x$ has a root which lies between $x = 1$ and $x = 2$.
\item Use the iteration $\mathrm { x } _ { \mathrm { n } + 1 } = \operatorname { cosec } \left( \mathrm { x } _ { \mathrm { n } } \right)$, with $x _ { 0 } = 1$, to find
\begin{enumerate}[label=(\roman*)]
\item the values of $x _ { 1 }$ and $x _ { 2 }$, correct to 5 decimal places,
\item this root of the equation, correct to 3 decimal places.
\end{enumerate}\item There is another root of $x = \operatorname { cosec } x$ which lies between $x = 2$ and $x = 3$.
Determine whether the iteration $\mathrm { x } _ { \mathrm { n } + 1 } = \operatorname { cosec } \left( \mathrm { x } _ { \mathrm { n } } \right)$ with $x _ { 0 } = 2.5$ converges to this root.
\item Sketch the staircase or cobweb diagram for the iteration, starting with $x _ { 0 } = 2.5$, on the diagram in the Printed Answer Booklet.
\end{enumerate}
\hfill \mbox{\textit{OCR MEI Paper 3 2020 Q5 [11]}}