OCR MEI Paper 3 2022 June — Question 9 2 marks

Exam BoardOCR MEI
ModulePaper 3 (Paper 3)
Year2022
SessionJune
Marks2
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSmall angle approximation
TypeShow gradient equivalence at origin
DifficultyEasy -1.8 This requires only finding dy/dx = cos(x), evaluating cos(0) = 1, and comparing to the gradient of y=x which is 1. It's a straightforward differentiation and substitution exercise with no problem-solving element, significantly easier than typical A-level questions.
Spec1.05e Small angle approximations: sin x ~ x, cos x ~ 1-x^2/2, tan x ~ x1.07k Differentiate trig: sin(kx), cos(kx), tan(kx)

9 Show that \(\mathrm { y } = \mathrm { x }\) has the same gradient as \(\mathrm { y } = \sin \mathrm { x }\) when \(\mathrm { x } = 0\), as stated in line 5 .

Question 9:
AnswerMarks Guidance
\(\frac{dy}{dx} = \cos x\)M1 1.1
\(\cos 0 = 1\) and this is the same as the gradient of \(y = x\)E1 2.2a
[2 marks]
## Question 9:

$\frac{dy}{dx} = \cos x$ | M1 | 1.1 | Attempt to use small angle approximations scores **M0**

$\cos 0 = 1$ and this is the same as the gradient of $y = x$ | E1 | 2.2a | Convincing completion not necessarily in words

**[2 marks]**

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9 Show that $\mathrm { y } = \mathrm { x }$ has the same gradient as $\mathrm { y } = \sin \mathrm { x }$ when $\mathrm { x } = 0$, as stated in line 5 .

\hfill \mbox{\textit{OCR MEI Paper 3 2022 Q9 [2]}}